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likoan [24]
10 months ago
14

The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical trial, results co

uld be analyzed with a formal hypothesis test with the alternative hypothesis of p0.5, which corresponds to the claim that the method increases the likelihood of having a girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the method, which of the following P-values would you prefer: 0.999, 0.5, 0.95, 0.05, 0.01, 0.001? Why?The P-value of ▼ 0.9990.950.050.010.50.001 is preferred because it corresponds to the sample evidence that most strongly supports the ▼ alternativenull hypothesis that the method ▼ isis not effective.

Mathematics
1 answer:
marusya05 [52]10 months ago
8 0

ANSWER: The P-value of 0.001 is preferred because it corresponds to the sample evidence that most strongly supports the alternative hypothesis that the method is effective.

<em>We chose the p-value of 0.001 because it is he smallest and the smaller the p-value is, the more probable it is.</em>

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Answer:

The answer to your question is:  40.8 g of NaN₃

Step-by-step explanation:

NaN₃ mass = ?

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Equation

                           2NaN₃      ⇒ 2Na  +  3N2

                          2 moles of NaN₃  -----------------   3 moles of N₂

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                          x = (1.2 x 2) / 3

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MW NaN₃ = 23 + 28

                = 51 g

                         51 g of NaN₃ ----------------- 1 mol

                         x                    ----------------- 0.8 mol

                         x = (0.8 x 51) / 1

                        x = 40.8 g of NaN₃

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600/50=12
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