384,000 bacteria would be present at the end of 7 hours if it doubles itself every hour.
Initial number of bacteria=3000
Number of bacteria at the end = initial number of bacteria * (base)ⁿ
where, n= number of hours
Number of bacteria at the end=3000*2⁷
=3000*128
=384,000
Therefore, there will be 384000 bacteria at the end of seven hour if the bacteria doubles itself every hour.
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