2.23 seconds is the cannons' total flight time.
What is Acceleration due to gravity ?
The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/ is its SI unit. Both magnitude and direction are present.
According to the information
A diagonal ball is launched at a 45° angle from the horizontal. The ball is being fired in a projectile motion. A projectile is a motion in which a body that has been discharged into space with a velocity U is allowed to fall freely while being affected by gravity.
The cannon ball's total flight time, T, can be represented as;
where T = 2Usin(theta)/g;
U is the ball's starting speed, which is 35 m/s.
The angle the ball makes with the horizontal is theta, which is equal to 45°.
The acceleration caused by gravity is g = 9.81 m/
Incorporating the provided data into the existing formula;
T = 35sin45°/9.81
T = 35×0.7071/9.81
T = 24.74/9.81
2.52 seconds later
2.23 seconds is the cannons' total flight time.
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Answer:
10259.6 m
Explanation:
We are given that
Radius of small wheel,r=0.17 m
Radius of large wheel,r'=0.92 m
Initial velocity,u=0
Time,t=2.7 minutes=162 s
1 min=60 s
Velocity,v=10m/s
Time,t'=13.7 minutes=822 s
Time,t''=4.1 minutes=246 s
Substitute the values
Substitute the values
Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m
Answer:
Part 1) Time of travel equals 61 seconds
Part 2) Maximum speed equals 39.66 m/s.
Explanation:
The final speed of the train when it completes half of it's journey is given by third equation of kinematics as
where
'v' is the final speed
'u' is initial speed
'a' is acceleration of the body
's' is the distance covered
Applying the given values we get
Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as
Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance
Thus total time of journey equals
Part b)
the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals
Answer:
(a) 4.0334Ω
(b)parallel
Explanation:
for resistors connected in parallel;
Req =3.03Ω , R1 =12.18Ω
R2=1/0.2479
R2=4.0334Ω
(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.
Req = R1+R2