(1) find the density of a substance if the mass of the substance is 150kg and dimension 20mby10mby5m
1 answer:
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Answer:
B) the sound source moves towards you at 100 m/sec
Explanation:
The Dopper Effect is a phenomenon that occur when there is relative motion between an observer and a source of a wave. When this situation occurs, there is an apparent shift in frequency of the wave, as observed by the observer.
The apparent frequency observed by the observer is given by
where
f is the original frequency of the wave
f' is the apparent frequency
v is the speed of the wave
is the velocity of the observer (positive if moving towards the source of the wave, negative otherwise)
is the velocity of the source (negative if moving towards from the observer, positive otherwise)
In this problem, we want to find the scenario in which the sound frequency is higher.
We see that in all 4 scenarios, the sound source is moving: this means we have to find the scenario in which the denominator of the equation is smaller.
First of all, we notice the sound source moves towards the observer, is negative, so the denominator is higher: this means that the correct option must be either A or B.
Also, we notice that since is negative, a value larger in magnitude will mean a smaller denominator: therefore, the correct answer will be
B) the sound source moves towards you at 100 m/sec
Since this situation will make the denominator of the formula the smallest possible.
Answer:
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N
(b) the force the light beam exerts is much too small to be felt by the man.
Explanation:
Given;
cross-sectional area of the man, A = 0.500m²
intensity of light, I = 35.5kW/m²
If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;
P = I/c
where;
P is the pressure of the incident light
I is the intensity of the incident light
c is the speed of light
F = PA
where;
F is the force of the incident light on the man
P is the pressure of the incident light on the man
A is the cross-sectional area of the man
F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N
Therefore, the force the light beam exerts is much too small to be felt by the man.