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aalyn [17]
3 years ago
15

Daisy made the graph shown to display the data recorded during an experiment. Daisy is studying the effect of soil on the growth

of plants. Three identical plants having a height of 15 cm were used for the experiment. The first plant was planted in Type A soil in 4 hours of sunlight, the second plant was planted in Type B soil in 6 hours of sunlight, and the third plant was planted in Type C soil in darkness. All other growing conditions of the plants were kept constant.
A bar graph titled Plant Growth is shown. The y axis, labeled Height in centimeters, goes from 0 to 3.50. The x axis, labeled Week, goes from 1 to 4. Each week has 3 bars, Type A soil, Type B soil, and Type C soil. For weeks 1 to 4, bars for Type A soil have heights of 1.25 centimeter, 1.50 cm, 1.75 cm, 2.00 cm, bars for Type B soil have heights of 2.00, 2.25, 2.50, and 2.75 centimeters, and bars for Type C soil have heights of 0.50, 0.75, 1.00, and 1.75 centimeters.

Which step in Daisy's scientific method was incorrect? A single variable was used Sunlight was not kept constant More than one type of soil was used Other growing conditions were not changed
Physics
2 answers:
andreev551 [17]3 years ago
3 0

im in flvs too if thats what this is but anyway im doing it right now and i believe it is sunlight was not kept constant


bearhunter [10]3 years ago
3 0

Answer:

The Sunlight was not kept constant.

Explanation:

Plants generally respond to stimuli, and majorly require sunlight during the process of photosynthesis. That is why the growth of the plants was affected by the rate exposure to sunlight.

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A ball is thrown horizontally at a speed of 16 m/s from the top of a cliff. If the ball hits the ground 6.0 s later, approximate
lina2011 [118]

Answer:

Y = 176.4 m

Explanation:

For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:

Y = V₀y*t + (0.5)gt²

where,

Y = Height = ?

V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)

t = time = 6 s

g = 9.8 m/s²

Therefore,

Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²

<u>Y = 176.4 m</u>

3 0
3 years ago
What is a highland? (A) An area of high or hilly land (B) A piece of land surrounded by water on three sides (C) A large area of
Karolina [17]

Answer:

A

Explanation:

A Highland is an area of mountains.

3 0
3 years ago
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In which scenario will the two objects have the greatest gravitational force
Brilliant_brown [7]

Answer: I think the answer C

Explanation:

7 0
2 years ago
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Donner le lien entre la consommation d,eau et l,aspect de votre peau c,est un dm note reponse​
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4 0
2 years ago
Two workers pull horizontally on a heavy box. but one pulls twice as hard as the other. The larger pull is directed at 21.0° wes
pantera1 [17]

Answer:

The  magnitude of F1 is

|F1|=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

Explanation:

<u>Net Force </u>

Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.  

The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.  

Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:

\displaystyle -2F\ sin21^o+F\ cos\alpha =0

The sum of the vertical components of F1 and F2 must equal the total force Ft

\displaystyle -2F\ cos21^o+F\ sin\alpha =460

Solving for \alpha in the first equation

\displaystyle cos\alpha =\frac{2F\ sin21^o}{F}=2sin21^o

\displaystyle cos\alpha =0.717=>\alpha =44.214^o

\displaystyle F(2cos21^o+sin\alpha)=460

\displaystyle F=\frac{460}{2cos21^o+sin\alpha}

\displaystyle F=\frac{460}{2cos21^o+sin44.214^o}

\displaystyle F=179.37\ N

The  magnitude of F1 is

|F1|=2*F=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

4 0
3 years ago
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