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aalyn [17]
3 years ago
15

Daisy made the graph shown to display the data recorded during an experiment. Daisy is studying the effect of soil on the growth

of plants. Three identical plants having a height of 15 cm were used for the experiment. The first plant was planted in Type A soil in 4 hours of sunlight, the second plant was planted in Type B soil in 6 hours of sunlight, and the third plant was planted in Type C soil in darkness. All other growing conditions of the plants were kept constant.
A bar graph titled Plant Growth is shown. The y axis, labeled Height in centimeters, goes from 0 to 3.50. The x axis, labeled Week, goes from 1 to 4. Each week has 3 bars, Type A soil, Type B soil, and Type C soil. For weeks 1 to 4, bars for Type A soil have heights of 1.25 centimeter, 1.50 cm, 1.75 cm, 2.00 cm, bars for Type B soil have heights of 2.00, 2.25, 2.50, and 2.75 centimeters, and bars for Type C soil have heights of 0.50, 0.75, 1.00, and 1.75 centimeters.

Which step in Daisy's scientific method was incorrect? A single variable was used Sunlight was not kept constant More than one type of soil was used Other growing conditions were not changed
Physics
2 answers:
andreev551 [17]3 years ago
3 0

im in flvs too if thats what this is but anyway im doing it right now and i believe it is sunlight was not kept constant


bearhunter [10]3 years ago
3 0

Answer:

The Sunlight was not kept constant.

Explanation:

Plants generally respond to stimuli, and majorly require sunlight during the process of photosynthesis. That is why the growth of the plants was affected by the rate exposure to sunlight.

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it lies in geometrical centre....

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GuDViN [60]

Answer:

F=X.F=mxq. 3. 1 N/kg=0.5kg g=9.80

4 0
3 years ago
The volume of an ideal gas is adiabatically reduced from 151 L to 80.6 L. The initial pressure and temperature are 1.50 atm and
Zolol [24]

Answer:

gas is dioatomic

T_f = 330.0 K

\eta = 7.07 mole

Explanation:

Part 1

below equation is used to determine the type Gas by determining \gamma value

\frac{V_{1}}{V_{F}}\gamma=\frac{P_{i}}{P_{f}}

where V_i and V_f is initial and final volume respectively

and P_i and P_f are initial and final pressure

\gamma = \frac{ln(P_f/P_i)}{ln(V_i/V_f)}

\gamma = \frac{ln(3.61/1.50)}{ln(151/80.6}

\gamma = 1.38

therefore gas is dioatomic

Part 2

final temperature in adiabatic process is given as

T_f = T_i*[\frac{v_i}{V_f}](^\gamma-1)

substituing value to get final temperature

T_f = 260*[\frac{151}{80.6}]^ {(1.38-1)}

T_f = 330.0 K

Part 3

determine number of moles by using following formula

\eta =\frac{PV}{RT}

\eta =\frac{1.013*10^{5}*0.151}{8.314*260}

\eta = 7.07 mole

4 0
3 years ago
Three charges, each of magnitude 10 nC, are at separate corners of a square of edge length 3 cm. The two charges at opposite cor
FinnZ [79.3K]

Answer:

The force exerted by three charges on the fourth is F_{resultant}=2.74\times10^{-5}\ \rm N

Explanation:

Given:

  • The magnitude of three identical charges, q=10\ \rm nC
  • Length of the edge of the square a=3 cm
  • Magnitude of fourth charge ,Q=3 nC

According to coulombs Law the force F between any two charge particles is given by

F=\dfrac{kQq}{r^2}

where r is the radial distance between them.

Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

F_{resultant}=\sqrt ((\dfrac{kQq}{L^2})^2+(\dfrac{kQq}{L^2} })^2)+\dfrac{kQq}{(\sqrt{2}L)^2}\\F_{resultant}=\dfrac{kQq}{L^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=\dfrac{9\times10^9\times10\times10^{-10}\times3\times10^{-9}}{0.03^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=2.74\times 10^{-5}\ \rm N

5 0
3 years ago
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