Answer:
B. Kinetic energy is created
Explanation:
Answer:
91.84 m/s²
Explanation:
velocity, v = 600 m/s
acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2
Let the radius of the loop is r.
he experiences a centripetal force.
centripetal acceleration,
a = v² / r
39.2 x r = 600 x 600
r = 3600 / 39.2
r = 91.84 m/s²
Thus, the radius of the loop is 91.84 m/s².
This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant.
<span> U = (1/2)kx^2
</span><span> U = (1/2)(5.3)(3.62-2.60)^2
</span> U = <span>
<span>2.75706 </span></span>J
1) A negatively charged ion is chloride
2) Moving from left to right, valence electrons increase by one.
3) The period number gives information about how many energy levels it has
4) Fluorine has a charge of 1–
5) Potassium and iodine form an ionic bond
The periodic table is an arrangement of elements into groups and periods based on their periodic properties.
In the periodic table, elements are arranged in groups and periods. There are 18 groups and 8 periods.
Chlorine is in group 17, there have seven outermost electrons hence the chlorine atom needs only one more electron in order to attain a stable octet. This is done by accepting one electron to form the negatively charged chloride ion.
As we move from one period to another, one extra electron is added to the outermost shell of elements. Hence, the valence electrons increases by one.
The period to which an element belongs shows you the number of shells or energy levels in the atom of that element.
Fluorine is in group 17. One electron is needed to achieve a stable octet. When an atom accepts one electron, its charge is 1–.
Bonding based on ionic charges occurs between metals and nonmetals. Potassium is a metal of group 1 and iodine is a non metal of group 17 hence they can bond together based on their ionic charges.
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Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.
-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.
-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.
-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)
-- Momentum = (mass) x (velocity)
After the shot, the momentum of the cannonball is
(0.02 kg) x (100 m/s ==> that way)
Momentum of the ball = 2 kg-m/s ==> that way.
-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .
Momentum of cannon = (5 kg) x (V m/s this way <==)
2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)
Divide each side by (5 kg):
V m/s = (2/5) m/s this way <==
Speed of recoil of the cannon = <em>-- 0.4 m/s</em>
