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Afina-wow [57]
1 year ago
6

Every day on his ride to school, Max sees some sedimentary rock. He starts to wonder: Could material from this sedimentary rock

ever form igneous rock?
Chemistry
1 answer:
Sloan [31]1 year ago
3 0

Material from this sedimentary rock ever forms igneous rock, <u>Option D. Yes, if the sedimentary rock is moved below Earth’s outer layer and exposed to energy from Earth’s interior, it can melt into liquid rock and form </u><u>igneous rock.</u>

Sedimentary rocks are shaped from pre-existing rocks or pieces of soon-as-dwelling organisms. They form from deposits that collect on this planet's floor. Sedimentary rocks regularly have special layering or bedding.

Igneous rock, or magmatic rock, is one of the 3 primary rock kinds, the others being sedimentary and metamorphic. Igneous rock is shaped via the cooling and solidification of magma or lava. The magma may be derived from partial melts of existing rocks in either a planet's mantle or crust.

Learn more about igneous rocks here:-brainly.com/question/6533375

#SPJ1

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Every day on his ride to school, Max sees some sedimentary rock. He starts to wonder: Could material from this sedimentary rock ever form igneous rock?

A. No, igneous rock can only form out of other igneous rocks. Sedimentary rock cannot change into igneous rock.

B. No, igneous rock forms under Earth’s outer layer due to energy from Earth’s interior, but the sedimentary rock is only at Earth’s surface.

C. Yes, if the sedimentary rock is exposed to energy from the sun at Earth’s surface for a long enough time, it can melt into liquid rock and form igneous rock.

D. Yes, if the sedimentary rock is moved below Earth’s outer layer and exposed to energy from Earth’s interior, it can melt into liquid rock and form igneous rock.

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Find the ph of a buffer that consists of 0.18 m ch3nh2 and 0.73 m ch3nh3cl (pkb of ch3nh2 = 3.35)?
ozzi
Hello!

First, we need to determine the pKa of the base. It can be found applying the following equation:

pKa=14-pKb=14-3,35=10,65

Now, we can apply the Henderson-Hasselbach's equation in the following way:

pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04

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Have a nice day!
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Need help with the question
Sloan [31]

Answer:

for a i think it is choice 2

for b i think it is the first choice

Explanation:

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Not sure if this is 100% but I hope it helps.
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