The third answer because there are two of each atom
Magnesium dichromate is the correct name of the compound MgCr₂O₇.
<h3>What is Molecular Formula ?</h3>
The chemical formula that gives total number of atoms of each element in one molecule of a compound is called Molecular Formula.
<h3>What is Oxidation State ?</h3>
Oxidation state is also known as oxidation number. It is defined as the atom is equal to the total number of electrons which have been removed from the element in order to form chemical bond with other atom.
Magnesium dichromate contains the Magnesium ion and chromate ions. Magnesium ion is represented as Mg⁺². Oxidation state of magnesium is +2. The chromate ion is represented as Cr₂O₇⁻². Oxidation state of chromate ion is -2.
Thus from the above conclusion we can say that The correct name of the compound MgCr₂O₇ is Magnesium dichromate.
Learn more about the Oxidation State here: brainly.com/question/8990767
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Answer:
2.387 mol/L
Explanation:
The reaction that takes place is:
- 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O
First we <u>calculate how many moles of each reagent were added</u>:
- HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl
- Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂
460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.
Now we <u>calculate how many moles of Ba(OH)₂ reacted</u>, by c<em>onverting the total number of HCl moles to Ba(OH)₂ moles</em>:
- 203.85 mmol HCl *
= 101.925 mmol Ba(OH)₂
This means the remaining Ba(OH)₂ is:
- 460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂
There are two OH⁻ moles per Ba(OH)₂ mol:
- OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻
Finally we <u>divide the number of OH⁻ moles by the </u><u><em>total</em></u><u> volume</u> (100 mL + 200 mL):
- 716.15 mmol OH⁻ / 300.0 mL = 2.387 M
So the answer is 2.387 mol/L
Explanation:
A neutralization is a type of double replacement reaction. a salt is the product of an acid-base reaction and is a much broader term then common table salt.
Example:-
(i) HCl + NaOH ---> NaCl + HOH
(ii) H2SO4 + 2NH4OH ---> (NH4)2SO4 + 2HOH.
