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beks73 [17]
3 years ago
10

Kia is doing an experiment in science lab. She is given a beaker containing 100 g of liquid. The beaker has markings on the side

for measuring volume. The water comes up to the 100 mL mark. Kia puts the liquid on a hot plate by mistake. By the time she realizes the mistake, half of her liquid has evaporated.
Kia still needs 100 g of liquid for her experiment. To find out how much liquid she has to replace, she needs to re-weigh her liquid. However, the balance she used before is now broken. The teacher tells Kia that she can tell how much water is left by looking. The water now comes up to the 50 mL mark.

How much mass does Kia's remaining water have?
Chemistry
2 answers:
Semmy [17]3 years ago
7 0
Kia's remaining water has a mass of 50g. You can set it up as a proportion knowing that 100ml of water has a mass of 100g and thus 50ml of water would weight 50g
tiny-mole [99]3 years ago
3 0

the correct answer is 50g

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Which is metal in modern periodic table​
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Answer:

The question was to be what is metal in modern periodic table?. Thank for understanding.

Now we come to business:

Metal in modern periodic table:is all the elements to the left of the line.

Explanation:

  • if you look at the modern periodic table diagram you will see a stair-stepped line starting at Boron(B),atomic number 5,and going all the way down to Polonium(Po), atomic number 84.Except for Germanium(Ge)and Antimony(Sb),all the elements to the left of the line can be classified as metals.

6 0
4 years ago
Using the periodic table to locate each element, write the electron configuration of(c) Re.
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Rhenium is a chemical element with the symbol Re and atomic number 75. The electron configuration of Re is [Xe] 6s^{2} 4f^{14} 5d^{5}.

<h3>How to write an electronic configuration?</h3>

1. Identify the given element and its atomic number from the periodic table.

2. Write the electron configuration by the energy level and the type of orbital first, then the number of electrons present in the orbital as superscript.

The easiest way to write the electronic configuration for any element is by   using a diagonal rule for electron filling order in the different subshells according to the Aufbau principle.

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5 0
2 years ago
why is Dalton credited with proposing the first atomic theory if Democrritus was talking about atoms 2,200 years earlier
Readme [11.4K]

Answer:Why is Dalton credited with proposing the first atomic theory if Democritus was talking about atoms almost 2,200 years earlier?

- Democritus' ideas were not supported by evidence

- Dalton's theory was the first scientific theory because it relied on scientific investigative processes.

- Dalton's theory was supported by evidence and repeated investigation.

Explanation:  1: Democritus' ideas were not supported by evidence

2: Dalton's theory was the first scientific theory because it relied on scientific investigative processes.

3: Dalton's theory was supported by evidence and repeated investigation.

5 0
3 years ago
If i have about 68.2 grams of H2S, how many moles do i have?
natita [175]

Answer:

2.1 mol

Explanation:

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6 0
4 years ago
Read 2 more answers
2. Nitrogen has two naturally occurring
kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0
3 years ago
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