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kolbaska11 [484]
3 years ago
14

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.25 grams of aluminum foil in a solut

ion of 0.40 grams of copper (II) chloride. A single replacement reaction takes place. What are the likely observations when the reaction stops? Unbalanced equation: CuCl2 + Al → AlCl3 + Cu
Chemistry
1 answer:
netineya [11]3 years ago
7 0

Answer: About 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture

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Answer:

0.79 g

Explanation:

Let's introduce a strategy needed to solve any similar problem like this:

  • Apply the mass conservation law (assuming that this reaction goes 100 % to completion): the total mass of the reactants should be equal to the total mass of the products.

Based on the mass conservation law, we need to identify the reactants first. Our only reactant is sodium bicarbonate, so the total mass of the reactants is:

m_r=m_{NaHCO_3}=2.36 g

We have two products formed, sodium carbonate and carbonic acid. This implies that the total mass of the products is:

m_p=m_{Na_2CO_3}+m_{H_2CO_3}

Apply the law of mass conservation:

m_r=m_p

Substitute the given variables:

m_{NaHCO_3}=m_{Na_2CO_3}+m_{H_2CO_3}

Rearrange for the mass of carbonic acid:

m_{H_2CO_3}=m_{NaHCO_3}-m_{Na_2CO_3}=2.36 g - 1.57 g=0.79 g

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4 years ago
A temperature of 37C is equivalent to a temperature of
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Answer 98.6 Fahrenheit
8 0
3 years ago
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Which of the following is not a possible termination step in the free radical chlorination of methane? Group of answer choices ∙
vagabundo [1.1K]

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Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product

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Explanation:

8 0
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