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Jobisdone [24]
4 years ago
9

Please help. ill make you BRAINLIEST

Physics
1 answer:
xeze [42]4 years ago
3 0

Answer:

because well I dont even know sorryy but you got this

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A MEMS-based accelerometer has a mass of m = 2 grams, an equivalent spring constant of k = 5 N/m, and an equivalent damping coef
pychu [463]

Answer:

The natural frequency = 50 rad/s = 7.96 Hz

Damping ratio = 0.5

Explanation:

The natural frequency is calculated in this manner

w = √(k/m)

k = spring constant = 5 N/m

m = mass = 2 g = 0.002 kg

w = √(5/0.002) = 50 rad/s

w = 2πf

50 = 2πf

f = 50/(2π) = 7.96 Hz

Damping ratio = c/[2√(mk)] = 0.1/(2 × √(5 × 0.002)) = 0.5

5 0
3 years ago
This reddish layer of the atmosphere of the Sun is not normally visible, but the ________________ may be seen briefly during a t
kupik [55]

Answer:

Chromosphere

Explanation:

The Chromosphere is one of the important internal layers of the sun, which lies above the layer of Photosphere. The Chromosphere has a thickness of about 3 to 5 km having a very high temperature, ranging from about 5000 to 20,000°C. Due to this extreme temperature and continuous nuclear fusion process that takes place at the core of the sun, there forms the reddish colored layer, which is usually not visible but can be observed during the time of a total solar eclipse, by the use of an ultraviolet telescope.

8 0
3 years ago
A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
LekaFEV [45]
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1

hmax = <span> –16(1)² + 32(1) + 6
hmax = 22

Therefore, first option is the correct answer.</span>
8 0
3 years ago
Read 2 more answers
If a ball is tossed straight up into the air, what position is its potential energy the greatest
zvonat [6]
Potential energy is the greatest when the the kinetic energy is the least. This occurs when the ball loses the energy to fly higher, and begins to fall back to the ground.
4 0
4 years ago
A radioactive sample has a count rate of 10,000 Bq. 24 days later the activity has fallen to 625 Bq. What is the half-life of th
joja [24]

Answer:

10000 Bq / 625 Pq = 16

Radioactivity has decreased by a factor of 16

2^4 = 16

So the sample has gone thru 4 half-lives

24 da / 4 = 6 da

6 da is the half-life

6 0
3 years ago
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