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3 years ago

An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of

Physics

1 answer:

blondinia [14]3 years ago

5 0

Answer:

v = 12.12 m/s

Explanation:

It is given that,

Radius of circle, r = 30 m

The coeﬃcient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

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Problem Page Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 28. g o

sergejj [24]

Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

Solution : Given,

Mass of $C_2H_6$ = 28 g

Mass of $O_2$ = 190 g

Molar mass of $O_2$ = 32 g/mole

Molar mass of $C_2H_6$ = 30 g/mole

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $C_2H_6$ and $O_2$ .

$\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{28g}{30g/mole}=0.933moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{190g}{32g/mole}=5.94moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

From the balanced reaction we conclude that

As, 2 mole of $C_2H_6$ react with 7 mole of $O_2$

So, 0.933 moles of $C_2H_6$ react with $\frac{7}{2}\times 0.933=3.26$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C_2H_6$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO_2$

From the reaction, we conclude that

As, 2 mole of $C_2H_6$ react to give 4 mole of $CO_2$

So, 0.933 moles of $C_2H_6$ react to give $\frac{4}{2}\times 0.933=1.87$ moles of $CO_2$

Now we have to calculate the mass of $CO_2$

$\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2$

$\text{ Mass of }CO_2=(1.87moles)\times (44g/mole)=82.3g$

Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

6 0

4 years ago

Why does changing the shape on an object have no affect on the density of that object?

Anna11 [10]

It is because change in the Mass of the object balances the change in the Volume of the object equally...........

8 0

3 years ago

If homeboy joe is pushing a box with force of 57.0 in the horizontal direction and -15.0 in the vertical direction. What is the

Ksenya-84 [330]

Answer:

The magnitude of joes net force is 58.9.

Explanation:

The magnitude of the net force is given by:

$F_{net} = \sqrt{F_{x}^{2} + F_{y}^{2}}$

Where:

$F_{x}$ : is the force in the horizontal direction = 57.0

$F_{y}$ : is the force in the vertical direction = -15.0

$F_{net} = \sqrt{(57.0)^{2} + (-15.0)^{2}} = 58.9$

Therefore, the magnitude of joes net force is 58.9.

I hope it helps you!

5 0

3 years ago

Rank the following in terms of increasing momentum:

ycow [4]

Answer:

Ranks based on momentum are

1. 1200 kg car going at 15 m/s.

2. 15 kg meteor going at a speed of 100 m/s.

3. 100 kg person running at 5 m/s.

4. 10000 kg train car at rest.

Explanation:

Product of a body’s mass and velocity gives the value of its momentum. It is given by the equation

$P=mv$

where is the mass of the object and is the velocity.

Calculating the values of momentum:

1. mass= 1200 kg, velocity= 15 m/s

$p=mv =1200 \times 15 = 18000 \ kg \ m/s$

2. mass= 15 kg, velocity= 1000 m/s

$p= 15 \times 1000 = 15000 \ kg \ m/s$

3. mass= 100 kg, velocity= 5 m/s

$p= 100 \times 5 = 500 kg \ m/s$

4. mass= 1000 kg, velocity= 0 m/s

$p= 10000 \times 0= 0 \ kg\ m/s$

6 0

4 years ago

Read 2 more answers

The temperature in the room is rising because the explosion is releasing _____ energy into the air, increasing the speed of the

svlad2 [7]

This is going to be heat energy. =)

4 0

3 years ago

Read 2 more answers