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FinnZ [79.3K]
3 years ago
11

A 5c charge experiences a force of 40n when put at a certain location in space. What is the electric field at that location?

Physics
1 answer:
stepladder [879]3 years ago
3 0
The 'strength' of the electric field is the force on 1C of charge at that point.

At this 'certain location', the field is 40/5 = 8 newtons per coulomb = <u>8 volts</u>
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What is the speed of a wave that has a wavelength of 0.4 m and a frequency of 10 Hz
Shkiper50 [21]
<span>speed = wavelength x frequency
speed = 0.4m X 10 Hz
speed = 4 m/s</span>
4 0
3 years ago
A 100kg bag of sand has a weight on 100 N. When dropped it's acceleration is what?​
Vesnalui [34]

Answer:

9.8m/s

Explanation:

acceleration due to gravity is independent of mass

7 0
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What is a target ceiling ?
zloy xaker [14]

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3 years ago
A proton, an electron, and a helium nucleus all move at speed v . Rank their de Broglie wavelengths from largest to smallest.
Varvara68 [4.7K]

Ranking of de Broglie wavelengths from largest to smallest is electron > proton > helium

  • De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
  • From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship

De Broglie's relationship is given by \lambda=\frac{h}{mv}      .....(1) , where λ  is known as de Broglie wavelength and m is mass , v is velocity , h = Plank’s constant.

From equation (1) wavelength and mass has an inverse relation .

Mass of helium is 4 times the mass of the proton and proton has a greater mass than electron.

According to equation (1) , less the mass higher will be the wavelength

Hence electron having less mass have higher wavelength and then proton and then helium having large mass will have less wavelength .

Thus, order should be electron > proton > helium .

Learn about de brogile wavelength more here :

brainly.com/question/16595523

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8 0
1 year ago
A cannon fired horizontally at 20 m/s from the top of a cliff lands 80m away. how tall is the cliff
Scorpion4ik [409]

Answer:

The height of the cliff is, h = 78.4 m

Explanation:

Given,

The horizontal velocity of the projectile, Vx = 20 m/s

The range of the projectile, s = 80 m

The projectile projected from a height is given by the formula

                            <em> S = Vx [Vy + √(Vy² + 2gh)] / g </em>

Therefore,  

                            h = S²g/2Vx²

Substituting the values

                             h = 80² x 9.8/ (2 x 20²)

                                = 78.4 m

Hence, the height of the cliff is, h = 78.4 m

8 0
3 years ago
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