A 5c charge experiences a force of 40n when put at a certain location in space. What is the electric field at that location?

1 answer:

3 0

The 'strength' of the electric field is the force on 1C of charge at that point.

At this 'certain location', the field is 40/5 = 8 newtons per coulomb = 8 volts

You might be interested in

Which features on mars point to the possibility of liquid water on the planet?

Stells [14]

In 2011 NASA researchers identified features on Mars known as Recuring Slope Lineae ( or RSL ). RSL are relatively dark and narrow features.They are thought to be a signs of salty liquid water on Mars. One hypothesis for RSL formation is that they form when underground bodies of salty water leak into the surface.
Answer: Recuring Slope Lineae.

7 0

3 years ago

Read 2 more answers

Water _____.

Mice21 [21]

Water expands when it freezes (that's why you should never put closed, fully filled water bottles in the freezer !)

6 0

3 years ago

Read 2 more answers

Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector

Sav [38]

Good morning.

We see that $\mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}$

The magnitude(norm, to be precise) can be calculated the following way:

$\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}$

Now the calculus is trivial:

$\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}$

7 0

3 years ago

A lamp that uses 100.0 watts of power requires a voltage of 210.0 volts. What is the resistance of the lamp?

alexandr402 [8]

Resistance = Voltage/Current
Wattage = Voltage * Current

 That means the current drawn by the lamp is equal to 100 watts divided by 210 volts.

Resistance = $\frac{210}{ \frac{100}{210} }$

6 0

2 years ago

Read 2 more answers

HELP PLEASE answer choices: W X Y Z

Gala2k [10]

I believe it would be x because you are trying to find the width of the wave but i could be wrong

6 0

2 years ago