Answer:
(D) 42.4N
Explanation:
Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.
Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is
F_net = 0 = F_g -2 * F_y
The vertical force of one cable (using the information in the drawing) is:
F_y = 30N * sin 45 deg = 21.21N
Now the weight can be determined:
0 = F_g - 2 * F_y
F_g= 2 * F_y = 2 * 21.21N = 42.4N
The weight of the frame is about 42.4N.
Answer:
The time taken by the student to climb is 12.25 seconds and work done is 2450 J.
Explanation:
Given that,
Mass of the student, m = 50 kg
The student climbs to a height of 5 meters at a constant speed.
The student's power output is 200.0 W, P = 200 W
The power of an object is given by work done divided by time taken. So,
(b) W is work done,
(b)
So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.
Answer:
120 watts
Explanation:
#1: 120 watts
#2: 667 watts
#3: 3 watts
#4: i forgot how to do this one
Are you asking how to plot a against t?
It depends what the motion is...
