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3 years ago

14

Create a group of 3-4 students. Using your cell phone flashlight and the filter, create a "blue" flashlight, "red" flashlight, a

nd "green" flashlight. Shine all three flashlights at the white index card. Describe what you observe.

1 answer:

Korvikt [17]3 years ago

4 0

Answer:

the light creates sorta a mixture of all the colors on the white index card.

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A girl runs 40m due south in 40 seconds an d then 20m due north in 10 secondsCalculate.

m_a_m_a [10]

Answer:

Average speed = 1.2 m/s

Average velocity = 0.4 m/s

Explanation:

Average speed = total distance/total time

Average speed = (40 + 20)/(40 + 10)

Average speed = 60/50

Average speed = 1.2 m/s

Average velocity = displacement/time

Now, she ran 40 m south and ran 20 m back north which is in the direction of where she began the journey.

Thus;

Displacement = 40 - 20 = 20 m

Average velocity = 20/50 = 0.4 m/s

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3 years ago

How much energy (in kWh) can you get from a 72 cell solar panel in one year?

Mumz [18]

Answer:72,000
Explanation:

4 0

3 years ago

a system of four particles moves along one dimension. the center of mass of the system is at rest, and the particles do not inte

Zinaida [17]

The velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.

The given parameters;

m1 = 1.45 kg, v1(t) = (6.09m/s) + (0.299m/s^2) × t

m2 = 2.81 kg, v2(t) = (7.83m/s) + (0.357m/s^2) × t

m3 = 3.89 kg, v3(t) = (8.09m/s) + (0.405m/s^2) × t

m4 = 5.03kg

The velocity of the center mass of the particles is calculated as;

McmVcm = m1v1 + m2v2 +m3v3+m4v4

Vcm= m1v1 + m2v2 +m3v3 +m4v4/ Mcm

0 = m1v1 + m2v2 +m3v3 +m4v4/ Mcm

m1v1 + m2v2 +m3v3+m4v4 = 0

m4v4 = -(m1v1 + m2v2 +m3v3)

v4 =-(m1v1 + m2v2 +m3v3)/ m4

The velocity of particle 1 at time, t = 2.83 s;

vi = 6.09 + 0.299× 2.83

v1 = 6.94 m/s

The velocity of particle 3 at time, t = 2.83 s;

v2 = 7.83 + 0.357 × 2.83

v2 = 8.84 m/s

The velocity of particle 3 at time, t = 2.83 s;

v3 = 8.09 + 0.405 × 2.83

v3 = 9.24 m/s

The velocity of particle 3 at time, t = 2.83 s;

v4 = - (m1v1 + m2v2 + m3v3)/m4

v4 = -(1.45×6.94 + 2.81×8.84 + 3.89×9.24)/5.03

v4 = -14.4 m/s

Thus, the velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.

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5 0

1 year ago

One object is thrown vertically upward with an initial velocity of 100 m/s and

gavmur [86]

We have that for the Question it can be said that The maximum height reached by the first <em>object</em> will be 100 times that of the other.

$(H_{max})_1=100*(H_{max})_2$

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s. The maximum height reached by the first object will be

that of the other.

a. 10,000 times

b. none of these

<em>c. </em><em>1000 times</em>

d. 100 times

<em>e.</em><em> 10 times</em>

Generally the equation for the velocity is mathematically given as

$v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}\\\\$

$(H_{max})_1=100*(H_{max})_2$

Therefore

The maximum height reached by the first <em>object</em> will be 100 times that of the other.

$(H_{max})_1=100*(H_{max})_2$

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2 years ago

What is the relationship between electric field lines and equipotential surfaces?

Tems11 [23]

An equipotential surface is a three-dimensional version of equipotential lines. * *Equipotential lines are always perpendicular to electric field lines* . The process by which a conductor can be fixed at zero volts by connecting it to the earth with a good conductor is called grounding.

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2 years ago