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3 years ago

14

Create a group of 3-4 students. Using your cell phone flashlight and the filter, create a "blue" flashlight, "red" flashlight, a

nd "green" flashlight. Shine all three flashlights at the white index card. Describe what you observe.

1 answer:

Korvikt [17]3 years ago

4 0

Answer:

the light creates sorta a mixture of all the colors on the white index card.

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A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t

viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

$mv+MV=(m+M)v'$

Here , $v'$ is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

$0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s$

Hence , this is the required solution .

3 0

3 years ago

A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for

olga_2 [115]

Answer:

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

3 0

3 years ago

A 2.5-kg book slides horizontally and falls from a shelf 3.0 m above the floor. How much work does the force of gravity do on th

frutty [35]

Answer:

73.5 N

Explanation:

W = PE = mgh = 2.5 * 9.8 * 3.0 = 73.5 N

7 0

3 years ago

Tania releases a javelin 1.2 meters above the ground with an initial vertical velocity of 20 meters per second. how long will it

Anarel [89]

This is an example of free fall;
For free fall the gravitational acceleration is -9.8 m/s²
From the equation;
S = ut -1/2gt², where S is the height above the ground, U is the initial vertical velocity, t is the time taken.
Therefore;
1.2 = 20t - 1/2(9.8)t²
1.2 = 20t -4.9t²
Thus; the equation is -4.9t² + 20t = 1.2, this is the appropriate answer.

4 0

3 years ago

A car with the mass of 18,000kg accelerates at the rate of 9m/s. what is the force being applied to the car?

Vika [28.1K]

Hope it cleared your doubt.

5 0

3 years ago