All categories

3 years ago

A Truck with a mass of 1500 kg is decelerated At a rate of 5m/s2. how much force did this require

Physics

1 answer:

Marianna [84]3 years ago

6 0

(1500 kg)*(5 m/s^2) = 7500 N

You might be interested in

goblinko [34]

Answer:

Explanation:

initial velocity u = 32.7 m /s

final velocity v = 50.3 m /s

displacement s = 44500 m

acceleration a = ?

v² = u² + 2 a s

50.3² = 32.7² + 2 x a x 44500

2530.09 = 1069.29 + 89000a

a .016 m /s²

time taken t = ?

v = u + at

50.3 = 32.7 + .016 t

t = 1100 s

6 0

3 years ago

Which equation can be used to solve for acceleration? <br><br>

antoniya [11.8K]

A = d/t
hope this helps x

3 0

4 years ago

Read 2 more answers

Acceleration is the magnitude of average velocity.

lina2011 [118]

Answer:

false

Explanation:

just did the question on apex, true was wrong

4 0

4 years ago

TRUE OR FALSE

Lynna [10]

Answer:

True

Explanation:

If you balance calorie intake it i very good FOR YA BODY

6 0

3 years ago

Read 2 more answers

The FM radio band in most places goes from frequencies of about 89 MHz to 106 MHz. How long is the wavelength of the radiation a

ohaa [14]

Answer:

2.83 m

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is given by

$\lambda=\frac{c}{f}$

where

$\lambda$ is the wavelength

$c=3.0\cdot 10^8 m/s$ is the speed of light

$f$ is the frequency

For the FM radio waves in this problem, we have:

$f_1=89 MHz=89\cdot 10^6 Hz$ is the minimum frequency, so the maximum wavelength is

$\lambda_2=\frac{c}{f_1}=\frac{3\cdot 10^8}{89\cdot 10^6}=3.37 m$

The maximum frequency is instead

$f_2=106 MHz=106\cdot 10^6 Hz$

Therefore, the minimum wavelength is

$\lambda_1=\frac{c}{f_2}=\frac{3\cdot 10^8}{106\cdot 10^6}=2.83 m$

So, the wavelength at the beginning of the range is 2.83 m.

8 0

3 years ago