This problems a perfect application for this acceleration formula:
Distance = (1/2) (acceleration) (time)² .
During the speeding-up half: 1,600 meters = (1/2) (1.3 m/s²) T²
During the slowing-down half: 1,600 meters = (1/2) (1.3 m/s²) T²
Pick either half, and divide each side by 0.65 m/s²:
T² = (1600 m) / (0.65 m/s²)
T = square root of (1600 / 0.65) seconds
Time for the total trip between the stations is double that time.
T = 2 √(1600/0.65) = <em>99.2 seconds</em> (rounded)
Answer:
Pressure will be 
Explanation:
We have given mass of the women m = 65 kg
Radius of the heels r = 0.578 cm = 0.00578 m
We have to find the pressure
We know that pressure is given by
So force F = mg = 65×9.8 = 637 N
Area 
So pressure 
Answer:
the rate of turn at any airspeed is dependent upon the horizontal lift component
Answer:
Acceleration is the change in velocity over the change in time = Δv/Δt. To do these problems, you need to find out how much the speed changed and over what period of time it changed.
Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes. Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):
Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ? (remember to put down the units)
Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes
Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ? (note that the acceleration is negative when you slow down)
I hope this helps you
Given :
You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.
To Find :
What is the ball velocity at the higher point that the ball reaches.
Solution :
We know, when ball is moving upward acceleration due to gravity is applied downward.
So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.
Therefore, ball velocity is 0 m/s at maximum height.
Hence, this is the required solution.
