V₁ = initial Volume of the balloon after it is blown up = 365 L
V₂ = new Volume of the balloon after it is taken outside = ?
T₁ = initial temperature of the balloon = 283 K
T₂ = new temperature of the balloon = 300 K
using the equation
V₁/V₂ = T₁/T₂
365/V₂ = 283/300
V₂ = 387 L
<span>0.002 moles is the answer </span>
Answer:
a. 
b. 
c. 
Explanation:
Hello,
a. By applying the given information, one obtains:

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

c. Here, the propane's combustion chemical reaction is stated:

This enthalpy of reaction is computed via:
Δ
Finally, since it is done for 20 lb of propane (
), the obtainable energy is:

Best regards.