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sdas [7]
3 years ago
8

Subsurface mining disturbs more land than surface mining true or false

Chemistry
1 answer:
Allisa [31]3 years ago
5 0

Answer:

False

Explanation:

Surface mining disturbs more land compared to subsurface mines.

During surface mining, huge mounds of earth is removed inorder to access mineral deposits. The deeper lying the deposit, the more the earth is removed and disturbed.

In subsurface mines, tunnels and a system of shaft are used to access the ore body. Data about the geometry and positioning of the ore helps to plan how to effectively access it.

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0.5 kg or 0.5 lb which is a larger quantity
masha68 [24]
The correct answer is 0.5 kg If you whant me to explaine pls tell me
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3 years ago
when solid pellets of sodium hydroxide (naoh) dissolve in water, the temperature of the water can rise dramatically. taking naoh
irga5000 [103]

ΔSsys  and ΔSsurr both have values larger than 0.

<h3>Entropy Change: What Is It?</h3>
  • Entropy change is a phenomena that measures the evolution of randomness or disorder in a thermodynamic system.
  • It has to do with how heat or enthalpy is converted during work.
  • More unpredictability in a thermodynamic system indicates high entropy.
  • Heat transport (delta Q) divided by temperature equals the change in entropy (delta S).
<h3>What causes variations in entropy?</h3>
  • When a substance is divided into several pieces, entropy rises.
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learn more about entropy change here

brainly.com/question/6364271

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8 0
1 year ago
¿Que ocurre cuando alteramos la temperatura de una disolución?
Gelneren [198K]

Answer: Explanation:

Temperatura. La solubilidad de un soluto en un determinado solvente principalmente depende de la temperatura. Para muchos sólidos disueltos en el agua líquida, la solubilidad aumenta con la temperatura hasta 100 °C,​ aunque existen casos que presentan un comportamiento inverso.

8 0
3 years ago
What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form
AnnyKZ [126]
<h3>Answer</h3>

HF

<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of \text{F}^{-} ions. The objective is to thus find its conjugate acid or base.

\text{F}^{-} contains no proton \text{H}^{+} and is unlikely to be a conjugate acid. Assuming that \text{F}^{-} is a conjugate base. Adding one proton to \text{F}^{-} would produce its conjugate acid.

\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)

Therefore \text{HF} is the conjugate acid of \text{F}^{-}. \text{HF} happens to be a weak acid. As a result, combining \text{F}^{-} with \text{HF} would produce a solution with large number of both the weak acid and its conjugate base, which is a buffer solution by definition.

4 0
3 years ago
A rock weighing 15.0g is placed in a graduated cylinder, displacing the volume from 25.0 mL to 36.2 mL. What is the density of t
valina [46]
Density is defined as mass/volume, and the volume is 36.2-25 mL
so just substitute into the equation to get the answer. 

Hope this helps. 
6 0
3 years ago
Read 2 more answers
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