<span>carbon + oxygen → carbon dioxide</span>
<span>0.570 M (note the capital M, this is molarity. Using m denotes molality.
Molarity is represented by moles of solute over the liters of solution. In this problem we are given the mass of the solute and volume of solution. The calculations is follows:
(15.7 g CaCO3/275 mL of solution) x (1 mole CaCO3/ 100.0869 g of CaCO3) x (1000 mL of solution/ 1 L of solution) = 0.570 M CaCo3.</span>
4
I don't want to say anything else
Answer:
3-ethoxy-3-ethyl-5-methylheptane
Explanation:
In this case, we have to identify the longest chain of carbon in this case the longest chain is made with 7 carbons. Then we have to assign carbon 1. In this case, carbon 1 is the one nearest to the ethoxy group. With this in mind, we will have a methyl on carbon 5, a methyl on carbon 3 and an ethoxy group in carbon 3, so the name would be 3-ethoxy-3-ethyl-5-methylheptane.
See figure 1
I hope it helps!