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neonofarm [45]
2 years ago
14

Triangle Inequality TheoremDetermine if a triangle can be formed with the given lengths. If so, classify the triangle by its ang

le.YESorNO

Mathematics
1 answer:
frozen [14]2 years ago
3 0

Given:-

7,20,12

To find:-

Wheather the given sides form a valid triangle.

So now let,

A=7,B=20,C=12

To check we use the condition,

A+B>C,B+C>A,C+A>B

Substituting the values we get,

7+20>12,20+12>7,12+7>20

In the above condition 12+7>20 is wrong.

So the condition fails and the given sides doesnt form a triangle.

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PLEASE HELP!!!!!!!!
Taya2010 [7]

Answer:

9

Step-by-step explanation:

A quadratic equation is

ax^{2} +b+c

The axis of symmetry is 1. This means that some value of

-b/2a =1.

f(0) represent one of the horinzontal roots. Since f(0) equal 0, the constant is 0.

Notice how x=1 is the line of symmetry. This means when x=4 and x=-2, the quadratic is equal. so consider this equation.

a(4)^{2} +b(4)= a(-2)^{2} +b(-2)=-24

16a+4b= -24

4a-2b=-24

Solve for a by elimination.

2(4a-2b=-24)= 8a-4b=-48

Add both equations.

(16a+4b=-24)+(8a-4b=-48)= 24a=-92

Solve for a.

24a=-92

a=-3

Subsitute to in for b.

16(-3)+4b=-24

-48+4b=-24

4b=24

b=6

This means a=-3

b=6

So b-a is

6+3=9

8 0
3 years ago
Read 2 more answers
Is h correct? someone help
Juli2301 [7.4K]

Answer:

No The correct Answer is "G"

Step-by-step explanation:

First lets find 300% as a number which is 3 ok so now

increase 10 by 300%

so 100%+300%=400%

and half of 400 which is 200%

so H is no correct g is

6 0
3 years ago
If 5x + 1 = 21 then x =
Advocard [28]

Answer:

X would equal 4

Step-by-step explanation:

5 x 4 is 20. And the equation was 5x + 1 = 21.

So, the answer would equal 20. Hope this helped!! :D

7 0
3 years ago
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Which equation represents this statement? The product of 12 and 5 less than the number x is 45
deff fn [24]
12(x-5)=45 This is the answer I hope so
3 0
3 years ago
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Please help I need it!!!
liraira [26]

Answer:

I think it is the first one i think

Step-by-step explanation:

3 0
3 years ago
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