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Sphinxa [80]
3 years ago
7

What is the mass of 975 mL of mercury? Its density is 13.5 g/mL

Chemistry
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

72.22 g

Explanation:

975 mL Mercury× 13.5 g/mL = 72.22 g

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A carbonated soft drink hs a large amount of water dissolved with ample amount of carbon dioxide. In this case, the solvent is water and carbon dioxide is the solute. In 2, for the reaction <span>CH3COOH = CH3COO + H+, CH3COOH is a Bronsted-Lowry acid because it releases a proton which is H+. </span>
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Find the number of ibuprofen molecules in a tablet containing 200.0 mg of ibuprofen (c13h18o2). express the amount to four signi
Musya8 [376]

First let us calculate for the molar mass of ibuprofen:

Molar mass = 13 * 12 g/mol + 18 * 1 g/mol + 2 * 16 g/mol

Molar mass = 206 g/mol = 206 mg / mmol

 

Calculating for the number of moles:

moles = 200 mg / (206 mg / mmol)

moles = 0.971 mmol = 9.71 x 10^-4 moles

 

Using the Avogadros number, we calculate the number of molecules of ibuprofen:

Molecules = 9.71 x 10^-4 moles * (6.022 x 10^23 molecules / moles)

<span>Molecules = 5.85 x 10^20 molecules</span>

4 0
2 years ago
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I need the answer today!
olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

<h3>S1:</h3>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S2:</h3>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

<h3>S3:</h3>

M = m/v

= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S4: </h3>

M = m/v

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8 0
2 years ago
A gas mixture is made up of kr (21.7 g), o2 (7.18 g), and co2 (14.8 g). the mixture has a volume of 23.1 l at 59 °c. calculate t
Scilla [17]

Answer:- partial pressure of Kr = 0.306 atm, partial pressure of oxygen = 0.264 atm and partial pressure of carbon dioxide = 0.396 atm

Total pressure is 0.966 atm

Solution:- moles of Kr = 21.7 g x (1mol/83.8g) = 0.259 mol

moles of oxygen = 7.18 g x (1mol/32g) = 0.224 mol

moles of carbon dioxide = 14.8 g x (1mol/44g) = 0.336 mol

Volume of container = 23.1 L and the temperature is 59 + 273 = 332 K

From ideal gas law equation, P = nRT/V

partial pressure of Kr = (0.259 x 0.0821 x 332).23.1 = 0.306 atm

partial pressure of oxygen = (0.224 x 0.0821 x 332)/23.1 = 0.264 atm

partial pressure of carbon dioxide = (0.336 x 0.0821 x 332)/23.1 = 0.396 atm

Total pressure of the gas mixture = 0.306 atm + 0.264 atm + 0.396 atm = 0.966 atm

4 0
3 years ago
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