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Ilya [14]
1 year ago
5

Draw a correct Lewis structure for XeI2 (Xe in middle, surrounded by I's ) that puts a 0 formal charge on all atoms. How many lo

ne pairs (unshared pairs) are on the central atom? --------------------------------------------------------------------------------------------------------------------------------------------------- 2) A 0.3876 gram sample of a gaseous compound occupies 142 mL at 150 degrees C and 775 torr. What is the molar mass of the compound? Assume ideal behavior. M = dRT/P M = molar mass Hint: you must convert torr to atm 760 torr = 1 atm Hint: you must convert oC to K by adding 273 Hint: you must convert mL to L
Chemistry
1 answer:
Alona [7]1 year ago
3 0

1) The Lewis structure will be:

Xe

|

I--I

In this structure, the xenon atom is surrounded by two iodine atoms, which are bonded to it through single bonds. Each iodine atom has one lone pair of electrons, for a total of 2 lone pairs on the central atom (xenon).

2) The molar mass of the gaseous compound is 0.416 g/mol.

To draw a correct Lewis structure for XeI2, we need to first count the number of valence electrons in the molecule. Xenon is a noble gas and has 8 valence electrons, while iodine has 7 valence electrons for a total of 23 valence electrons. To satisfy the octet rule and put a 0 formal charge on all atoms, we can use the following Lewis structure:

Xe

|

I--I

To find the molar mass of the gaseous compound, we can use the ideal gas law:

M = dRT/P

Where M is the molar mass, d is the density, R is the ideal gas constant, T is the temperature, and P is the pressure.

Given that the density of the gas is 0.3876 grams/142 mL = 0.002736 grams/mL, the temperature is 150 + 273 = 423 K, the pressure is 775 torr = 775/760 atm = 1.0132 atm, and the ideal gas constant is 0.08206 L·atm/mol·K.

We can calculate the molar mass as follows:

M = (0.002736 g/mL) * (0.08206 L·atm/mol·K / (1.0132 atm)) * (423 K)

M = 0.416 g/mol

Learn more about molar mass, here brainly.com/question/12127540

#SPJ4

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3 0
3 years ago
Assuming that seawater is a 3.50 mass % aqueous solution of NaCl, what is the molality of seawater?
Fantom [35]

Hey there!

Consider 100 g of solution:

Mass of NaCl = 3.50% of mass of seawater

( 3.50 / 100 ) * 100 => 3.50 g

Number of moles as shown below:

Molar mass NaCl = 58.44 g/mol

n = Mass / molar mass

n = 3.50 / 58.44 => 0.059 moles of NaCl

Mass of sweater:

Mass of solution -  Mass of NaCl

100 -  3.50 = 96.5 g

96.5 g in Kg :

96.5 / 1000 => 0.0965 Kg

Therefore ,calculate molality  by using  the  following formula:

molality =  number of moles  of solute / mass of solution

molality = 0.059 / 0.0965

molality = 0.61 m


Hope That helps!

7 0
3 years ago
study the diagram and answer the following questions. a. Name A and B. b. Which element is it? Write its name and B symbol. p*=
Oksana_A [137]

Ai. A is called nucleus

Aii. B is called electron shell

B. The name of the element is Neon and the symbol of the element is Ne.

Ci. The atomic mass of the element is 20.

Cii. The atomic number of the element is 10

Di. The element belongs to group 18.

Dii. The element belongs to period 2.

E. The element has a valency of 8

A. Determination of the name of A and B

In the diagram given above, A is called the nucleus because it contains the neutrons and the protons of the atom.

B is called the electron shell because it contains the electrons of the atoms

B. Determination of the name and symbol of the element.

From the diagram given above,

The element has 10 protons. This simply means that the atomic number of the element is 10.

Comparing the atomic number of the element with those in the periodic table, the element is Neon with a symbol of Ne.

C. Determination of the atomic mass and atomic number.

Ci. Determination of the mass number

Proton = 10

Neutron = 10

<h3>Mass number =?</h3>

Mass number = Proton + Neutron

Mass number = 10 + 10

<h3>Mass number = 20</h3>

Thus, the atomic mass of the element is 20.

Cii. Determination of the atomic number.

The atomic number of an element is simply the number of protons in the atom of the element.

Proton = 10

Therefore,

Atomic number = proton = 10

Thus, the atomic number of the element is 10

D. Determination of the group and period.

Di. The group to which an element belongs to can be obtained by simply calculating the number of electrons in the outermost shell of the atom.

From the diagram given above, the outermost shell has 8 electrons. This suggest that the element has completely filled outermost shell.

Therefore, the element belongs to group 18 (i.e the noble gas)

Dii. The number of electron shell talks about the period to which and element belongs to.

From the diagram given above, the element has 2 electron shells.

Therefore, the element belongs to period 2

E. Determination of the valence electron(s)

The valence electron(s) is the number of electrons in the outermost shell of the atom.

From the diagram given above,

The outermost shell has 8 electrons.

Therefore, the element has 8 valence electrons

Learn more: brainly.com/question/5352570

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