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Paraphin [41]
4 years ago
8

Reread the poem by siegfried sassoon what does it suggest about the effects of trench warfare

Chemistry
1 answer:
leva [86]4 years ago
8 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

<span>It shows that trench warfare was brutal and dehumanizing and amounted to suicide for soldiers.</span>
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A student is building an electrical circuit. Which material should she choose for wires, and why.
r-ruslan [8.4K]

D. A metal such as copper, because its atom have very mobile electrons         - A-p-e-x verified!

<u>Have a Great Day!</u>

3 0
3 years ago
Ulfur dioxide gas can react in the presence of oxygen and vanadium(V) oxide to form sulfur trioxide. Sulfur trioxide is the only
LenaWriter [7]

According to the illustration, the vanadium (V) oxide would be a catalyst.

<h3>What are catalysts?</h3>

Catalysts are substances that are utilized in reactions that are not themselves consumed in reactions but only speed up the rate of the reactions.

Catalysts speed up the rate of reactions by lowering the activation energy of the reactants.

Sulfur dioxide reacts with oxygen to produce sulfur trioxide. The vanadium (v) oxide is not consumed in the reaction. Thus it only serves as a catalyst.

More on catalysts can be found here: brainly.com/question/12260131

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4 0
3 years ago
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
olasank [31]

Answer: It will take 8.2 minutes until the concentration decreases to 0.055 M

Explanation:

The time after which 99.9% reactions gets completed is 40 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{13min}=0.053min^{-1}

b)  Time taken for 0.085 M to decrease to 0.055 M

t=\frac{2.303}{0.053}\log\frac{0.085}{0.055}

t=8.2min

Thus it will take 8.2 minutes until the concentration decreases to 0.055 M

5 0
3 years ago
How many grams of H2Oare produced when 5.38g of O2<br> is reacted?
likoan [24]

Answer:

I think this answer should be 2.33 g H2O

6 0
3 years ago
1.How many milliliters of an aqueous solution of 0.157 M aluminum bromide is needed to obtain 13.4 grams of the salt?
trasher [3.6K]

Answer:

The answer to your question is:

1.- 320 ml

2.- 0.63 M

Explanation:

Data

V = ?   AlBr₃ = 0.157 M

mass = 13.4 g

Process

MW ALBr₃ = 27 + (80x3) = 267 g

                                267 g -------------------- 1 mol

                                13.4 g   ------------------  x

                                x = (13.4 x 1) / 267

                               x = 0.05 moles

Volume = 0.05/ 0.157

             = 0.320 l or 320 ml

2.-

NaNO₃ mass = 20.2 g

V = 375 ml

Molarity = ?

MW = 23 + 14 + 48 = 85g of NaNO₃

                          85 g of NaNO₃ -----------------   1 mol

                          20.2 g               -----------------   x

                         x = (20.2 x 1) / 85

                         x = 0.24 mol

Molarity = 0.24 / 0.375

             = 0.63                

4 0
3 years ago
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