Answer:
3.2 x 10²¹molecules
Explanation:
Given parameters:
Volume of nitrogen gas = 120cm³
Unknown:
Mass of nitrogen gas = ?
Number of molecules = ?
Solution:
To solve this problem, note that;
1 mole of gas occupies a volume of 22.4L at STP
Now;
convert 120cm³ to L ;
1000cm³ = 1L
120cm³ gives 0.12L
Since;
22.4L of gas has 1 mole at STP
0.12L of gas will have 
= 0.0054mole at STP
So;
Mass of N₂ = number of moles x molar mass
Molar mass of N₂ = 2(14) = 28g/mol
Mass of N₂ = 0.0054 x 28 = 0.15g
Now;
1 mole of a gas will have 6.02 x 10²³ molecules
0.0054 mole of N₂ will contain 0.0054 x 6.02 x 10²³ =
3.2 x 10²¹molecules
<u>Answer:</u> The equilibrium partial pressure of NO is 0.0034 atm
<u>Explanation:</u>
For the given chemical equation:
The expression of 
for above equation follows:
We are given:
Equilibrium partial pressure of 
= 0.0159 atm
Equilibrium partial pressure of NOBr = 0.0768 atm
Putting values in above equation, we get:
Hence, the equilibrium partial pressure of NO is 0.0034 atm
Electronegativity is the tendency of the element to attract shared pair of electron towards itself in bonded condition.
Ionisation enrgy is the amount of energy required to remove the outermost electron from neutral gaseous atom
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