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2 years ago

13

How many grams of hydroxide pellets, NaOh are required to prepare 50.0ml of a 0.150 M solution ?

2 answers:

Firlakuza [10]2 years ago

6 0

(O.0500L) x (0.150mo/L)x(39.997 15 g NaOh/mol)=0.300 g NaOh

ANSWER A

horrorfan [7]2 years ago

5 0

The correct answer is E10.

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Explanation:

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Σ $P_g_a_s$ $= P_1+P_2+P_3+...+P_n$

The prompt is trying to confuse you, but it actually tells us the pressure of the mixture to be 1 atm, but this can be converted to torr. Furthermore, we are informed only three gases are in the mixture: diatomic nitrogen, diatomic oxygen, and carbon dioxide:

$P_g_a_s=1 \ atm = 760 \ torr= P_N_2+P_O_2+P_C_O_2\\760 \ torr = 582.008 \ torr + P_O_2 \ + 0.285 \ torr$

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