C9H20 + 14O2 --> 9CO2 + 10H2O
Correct answer is <span>Fuels do not have to be purchased to generate power.</span>
Answer:
Identify the "given" information and what the problem is asking you to "find."
Given : Cl2O7
Find: % Composition (% Cl and %O)
List other known quantities.
Mass of Cl in 1 mol Cl2O7 , 2 Cl : 2 x 35.45 g = 70.90 g
Mass of O in 1 mol Cl2O7 , 7 O: 7 x 16.00 g = 112.00 g
Molar mass of Cl2O7 = 182.90 g/mol
- The substance that made up of a particular mixture can be regarded as Solute and solvent
- A mixture can be regarded as material which is made up of more than one different Chemical substance or substances , whereby they are not chemically combined.
- Substance could be any matter such as <em>salt, rice, and or compounds</em>
- A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
- <em>solutions</em>
- <em> suspensions </em>
- <em> colloids</em>.
- A mixture could be in this form <em>(Solute + solvent = solution)</em>
Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>
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Answer:
V = 12.5 L
Explanation:
Given data:
Volume of NO = 15.0 L
Temperature and pressure = standard
Volume of nitrogen gas produced = ?
Solution:
Chemical equation:
6NO + 4NH₃ → 5N₂ + 6 H₂O
Number of moles of NO:
PV = nRT
n = PV/RT
n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K
n = 15.0 atm.L / 22.43 atm.L /mol
n = 0.67 mol
now we will compare the moles of No and nitrogen gas.
NO : N₂
6 : 5
0.67 : 5/6×0.67 = 0.56
Volume of nitrogen gas:
PV = nRT
1 atm × V = 0.56 mol × 0.0821 atm.L /mol.K × 273.15 K
V = 12.5 atm.L / 1 atm
V = 12.5 L
