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Alika [10]
1 year ago
13

Based on the image below, which item is your limiting reactant?(A) Ice cream scoopB) Cone(C) Cherry

Chemistry
1 answer:
liubo4ka [24]1 year ago
4 0

According to the image, we can say that to form an ice cream unit you need 1 scoop of ice cream, 1 cone, and 1 cherry. In other words, the ratio between all the reactants is 1 to 1. Therefore, the limiting reactant will be the one with the least number of units.

If we count the amount of each of the reactants we have:

• 10 scoops of ice cream

,

• 7 cones

,

• 12 cherries

In less quantity are the cones, that is to say, that at most we can assemble 7 ice creams. Therefore, the limiting reactant will be the cone.

Answer: (B) Cone

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Using the temperature change provided, which of the following best describes the direction of energy flow in this reaction
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Answer:

: the answer is C

Explanation:

:State the law of conservation of energy.

Define and endothermic process.

Define an exothermic process.

Make conversions involving heat units.

7 0
3 years ago
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Which of the following is the best hypothesis?
DerKrebs [107]

Answer:

B.) If sodium carbonate is added to vinegar, the reaction will absorb heat.

Explanation:

A.) is incorrect because this is not testable. Rather, it is just an opinion that cannot be proven correct or incorrect.

B.) is correct because this statement is testable. Tests need to be run to determine the accuracy of the statement.

C.) is incorrect because this statement explains something that does not need to be tested. It is an example of a physical change when one tears a piece of paper.

D.) is incorrect because this is already a true statement. It is obvious that not all reactions absorb/release heat. While tests could be run to further prove this statement true, it is already considered accurate.

4 0
2 years ago
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The ka for hcn is 4.9 ⋅ 10-10. What is the value of kb for cn-?
marusya05 [52]

Answer:

kb = 2,0x10⁻⁵

Explanation:

The ka for HCN is:

HCN ⇄ H⁺ + CN⁻; ka = 4,9x10⁻¹⁰ <em>(1)</em>

The inverse reaction has an equilibrium constant of:

H⁺ + CN⁻ ⇄ HCN k = 1/4,9x10⁻¹⁰ = 2,0x10⁹ <em>(2)</em>

As the equilibrium of the water is:

H₂O ⇄ H⁺ + OH⁻; kw = 1x10⁻¹⁴ <em>(3)</em>

The sum of (2) + (3) gives:

H₂O + CN⁻ ⇄ HCN + OH⁻; kb = kw×k = 1x10⁻¹⁴×2,0x10⁹ =

2,0x10⁻⁶; <em>kb = 2,0x10⁻⁵</em>

<em />

<em>-In fact, the general formula to convert from ka to kb is:</em>

<em>kb = kw / ka-</em>

<em />

I hope it helps!

5 0
3 years ago
What do all codes such as morse and brallie have in common
astra-53 [7]

Answer: Morse code and Braille use representations to form messages.

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-also a similarity is that braille letters are made of 1 to 6 dots, and Morse code is also made of 1 to 6 dots and dashes

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4 0
3 years ago
In a gas grill, 29 lbs propane C3H8 are
dimulka [17.4K]

Answer : The mass of combustion products formed are 134 lbs.

Explanation :

The balanced chemical reaction will be:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Given :

Mass of C_3H_8 = 29 lbs = 13154.2 g

conversion used : 1 lbs = 453.592 g

Molar mass of C_3H_8 = 44 g/mole

First we have to calculate the moles of C_3H_8.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{13154.2g}{44g/mole}=298.9moles

Now we have to calculate the moles of CO_2 and H_2O.

From the balanced chemical reaction we conclude that,

As, 1 mole of C_3H_8 react to give 3 moles of CO_2

So, 298.9 mole of C_3H_8 react to give 298.9\times 3=896.7 moles of CO_2

and,

As, 1 mole of C_3H_8 react to give 4 moles of H_2O

So, 298.9 mole of C_3H_8 react to give 298.9\times 4=1195.6 moles of H_2O

Now we have to calculate the mass of CO_2 and H_2O.

Molar mass of CO_2 = 44 g/mole

Molar mass of H_2O = 18 g/mole

\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass }CO_2

\text{Mass of }CO_2=896.7mole\times 44g/mole=39454.8g=86.98lbs

and,

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass }H_2O

\text{Mass of }H_2O=1195.6mole\times 18g/mole=21520.8g=47.44lbs

The total mass of products = Mass of CO_2 + Mass of H_2O

The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs

Therefore, the mass of combustion products formed are 134 lbs.

6 0
3 years ago
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