The question is incomplete, the complete question is shown in the image attached to this answer.
Answer:
139.13
Explanation:
The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.
We obtain the relative atomic mass of Likhitium as follows;
(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)
61.7 + 73.2 + 0.7 + 3.53 = 139.13
Hence the relative abundance of Likhitium is 139.13
Explanation:
Specific heat capacity can be calculated using the following equation: q = mc∆T In the equation q represents the amount of heat energy gained or lost (in joules ), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g °C), and ∆T is the temperature change of the substance
Answer:
The value is 
Explanation:
From the question we are told that
The mass of saxitoxin is 
The volume of water is 
The osmotic pressure is 
The temperature is 
Generally the osmotic pressure is mathematically represented as
Here R is the gas constant with value
and C is the concentration of saxitoxin
So
Generally the number of moles of saxitoxin is mathematically represented as
=> 
=> 
Generally the molar mass of saxitoxin is mathematically represented as
=> 
=>
Answer:
Remain unchanged.
Explanation:
The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.
The initial sample has a molecular formula of MnSO₄·H₂O. This molecule is a hydrate as it has a unit of water within its structure for every molecule of MnSO₄. This sample is being dehydrated to remove the water to give.
MnSO₄·H₂O → MnSO₄ + H₂O
MnSO₄·H₂O has a molecular mass of 169.02 g/mol. While MnSO₄ has a molecular mass of 151 g/mol. Water has a molecular mass of 18.02 g/mol. We now can use the ratio of the mass of water to the mass of the initial sample to determine the percentage of each component by mass.
% water by mass:
18.02/169.02 x 100% = 10.7% Water by mass.
% MnO₄ by mass:
151/169.02 x 100% = 89.3% MnSO₄ by mass.
Water makes up 10.7% of the initial mass of MnSO₄·H₂O.
