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3 years ago

What is the difference between luminous objects and non luminous objects

Chemistry

2 answers:

AveGali [126]3 years ago

8 0

Answer:

Objects that can emit light energy by themselves are known as luminous objects. Objects that cannot emit light energy by themselves are known as non-luminous objects.

Explanation:

Kruka [31]3 years ago

8 0

Explanation:

<em><u>Luminous objects</u></em>:- The objects that can emit light energy by themselves are known as luminous objects.

Objects like the sun that give out or emit light of their own are luminous objects.

Other examples of luminous bodies are Electric bulb, torch etc.

<em><u>Non-luminous objects</u></em>:- the objects that can not emit light energy by themselves are known as Non- luminous objects.

Objects like the moon that do not give out or emit light of their own are Non- luminous objects.

Moon is an example of a non-luminous object as we can see the moon because it reflects light from the sun.

Other examples of Non luminous bodies are pen, pencil, chair, wood etc.

Luminosity – It is defined as the luminous intensity in a particular direction; or we can say it is the apparent brightness of an image.

The brightness of a star is defined as the total energy radiated in unit time. It is related to the surface area (A) and the effective temperature (TT) ( the temperature of a black body having the same radius as the star and radiating the same amount of energy per unit area in one second ) by a form of Stefan’s law, here is given by

⇒L=AσT4⇒L=AσT4

where

σ is the Stefan’s constant and L is the luminosity.

Note:

The laptop screen, mobile screen you are looking at right now is luminous but the page of your book is a non-luminous object, which is why you need a light on to read it.

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Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an

Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is $1.68*10^{-4} M$ .

Explanation:

For the first equlibria;

initial concentration of $H_{2}C_{3}H_{2}OH=0.15$

initial concentration of $HC_{3}H_{2}O_{4}^{-} =0$

initial concentration of $H^{+} =0$

Let concentration change of $H_{2}C_{3}H_{2}OH=-x$

Let concentration change of $HC_{3}H_{2}O_{4}^{-} =+x$

Let concentration change of $H^{+} =+x$

Let concentration in equilibrium state of $H_{2}C_{3}H_{2}OH=0.15-x$

Let concentration in equilibrium state of $HC_{3}H_{2}O_{4}^{-} =x$

Let concentration in equilibrium state of $H^{+} =x$

Therefore, $Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}$

$x^{2}+0.0015x-0.000225=0$

Which is a quadratic equation in x, solving it gives;

$x=0.01427$

Therefore, $HC_{3}H_{2}O_{4}^{-} =x= 0.01427M$

Now for the second equlibria;

initial concentration of $HC_{3}H_{2}O_{4}^{-}=0.01427$

initial concentration of $C_{3}H_{2}O_{4}^{2-} =0$

initial concentration of $H^{+} =0$

Let concentration change of $HC_{3}H_{2}O_{4}^{-}=-x$

Let concentration change of $C_{3}H_{2}O_{4}^{2-} =+x$

Let concentration change of $H^{+} =+x$

Let concentration in equilibrium state of $HC_{3}H_{2}O_{4}^{-}=0.01427-x$

Let concentration in equilibrium state of $C_{3}H_{2}O_{4}^{2-} =x$

Let concentration in equilibrium state of $H^{+} =x$

Therefore, $Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}$

$2.854*10^{-8}-(2.0*10^{-6})x=x^{2}$

Therefore, $C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M$

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

4 0

1 year ago

1. 3.311 * 10^24 particles=_______________moles? 2. 126 grams of H2O =______________________moles of moles? whats the answers

Vladimir [108]

1. You can use Avogadro’s number, 6.022x10^23 atoms/mole, to answer this one.

(3.311x10^24/6.022x10^23) = 5.498 moles of substance

2. H2O has a formula weight approximately equal to 18 grams. Dividing the given amount by the formula weight of water will tell us the number of moles present.

126/18 = 7 moles H2O

4 0

3 years ago

The equilibrium constant for the reaction of fluorine gas with bromine gas at 300 K is 54.7 and the reaction is: Br2(g) + F2(g)

alisha [4.7K]

Answer:

The correct answer is 0.024 M

Explanation:

First we use an ICE table:

Br₂(g) + F₂(g) ⇔ 2 BrF(g)

I 0.111 M 0.111 M 0

C -x -x 2 x

E 0.111 -x 0.111-x 2x

Then, we replace the concentrations of reactants and products in the Kc expression as follows:

Kc= $\frac{[BrF ]^{2} }{[ F_{2} ][Br_{2} ]}$

Kc= $\frac{(2x)^{2} }{(0.111-x)(0.111-x)}$

54.7= $\frac{4x^{2} }{(0.111-x)^{2} }$

We can take the square root of each side of the equation and we obtain:

7.395= $\frac{2x}{(0.111-x)}$

0.111(7.395) - 7.395x= 2x

0.82 - 7.395x= 2x

0.82= 2x + 7.395x

⇒ x= 0.087

From the x value we can obtain the concentrations in the equilibrium:

[F₂]= [Br₂]= 0.111 -x= 0.111 - 0.087= 0.024 M

[BrF]= 2x= 2 x (0.087)= 0.174 M

So, the concentration of fluorine (F₂) at equilibrium is 0.024 M.

8 0

3 years ago

How do you think you results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4

makkiz [27]

Answer:

Due to weak oxidizing agent.

Explanation:

In my opinion the results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4 because K2Cr2O7/H2SO4 is weak oxidizing agent as compared to KMnO4. An oxidizing agent is a substance that has the ability to oxidize other substances means that accept their electrons so that's why the results of strong oxidizing agent is different than weak oxidizing agent.

3 0

3 years ago

babymother [125]

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2) By removing the jaguar from the food web, we are removing one of the predators. This can cause a surplus in both the population of the mammals ( rabbit and the other one) because there is not something that is actively eating and keeping the numbers at bay. Essentially, if you remove the jaguar you will mess up the loop, causing an increase of population that could possibly cause harm. Also, by taking the jaguar out of the food web, the decomposers would not be able to decompose fecal, animal carcasses, etc. because the jaguar is not actively killing something and furthering along this process. Hope this helps!

7 0

2 years ago

What is the difference between luminous objects and non luminous objects ​

What is the difference between luminous objects and non luminous objects