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lana [24]
3 years ago
14

Calculate the mass volume percent of a NaCl solution in which 186 g of NaCl is dissolved in enough water to give a total volume

of 3.80 L
Chemistry
1 answer:
NISA [10]3 years ago
8 0
<h3>Answer:</h3>

48.95% (m/v)

<h3>Explanation:</h3>

From the question we are given;

  • Mass of solute, NaCl is 186 g
  • Volume of the solvent, water as 3.80 L or 380 mL

We are required to calculate the mass volume percent of solution;

How do we calculate the mass volume percent of a solution?

  • To calculate the mass volume percent, we use the formula,

Mass volume percent = (mass of solute in g/Volume of solvent in mL) 100

                                    = (186 g ÷ 380 mL)100

                                    = 48.95%

Therefore, the mass volume percent of a NaCl solution is 48.95% (m/v).

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What factors affect the dynamic state of equilibrium in a chemical reaction and how?
yanalaym [24]

Answer:

Only changes in temperature will influence the equilibrium constant K_c. The system will shift in response to certain external shocks. At the new equilibrium Q will still be equal to K_c, but the final concentrations will be different.

The question is asking for sources of the shocks that will influence the value of Q. For most reversible reactions:

  • External changes in the relative concentration of the products and reactants.

For some reversible reactions that involve gases:

  • Changes in pressure due to volume changes.

Catalysts do not influence the value of Q. See explanation.

Explanation:

\displaystyle K_c = {e}^{\Delta G/(R\cdot T)}.

Similar to the rate constant, the equilibrium constant K_c depends only on:

  • \Delta G the standard Gibbs energy change of the reaction, and
  • T the absolute temperature (in degrees Kelvins.)

The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium Q = K_c the two processes balance each other. The concentration of each species will stay the same.

Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.

  • Changes in concentration influence the number of particles per unit space.
  • Changes in temperature influence both the rate of collision and the percentage of particles with sufficient energy of reaction.

For reactions that involve gases,

  • Changing the volume of the container will change the concentration of gases and change the reaction rate.

However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.

8 0
3 years ago
I just need help plz!
Nesterboy [21]

Answer:

<u>Graphene</u> is a nanomaterial that is often used with other compounds to desalinate and decontaminate water.

The electrical behavior of semiconductor devices and electronics can be engineered using a process called <u>Doping</u>

Explanation:

4 0
2 years ago
Which sample has more atoms in it? 150.0 g of gold or 10.0 g of lithium.
Deffense [45]

Answer:150g of gold

Explanation: There is a lot more gold and gold is significantly significantly more dense than lithium

6 0
3 years ago
What is the formula for percent yield
Sindrei [870]
I think it is 89.3%?
3 0
3 years ago
How many moles are there in 7.5 L Of H2
True [87]
So multiply number of moles x number of atoms/mole = 1.8066 x 10^24 atoms of H2. One mole of any gas at STP has a volume of 22.4 L. So first determine the number of moles of gas you have.
for example do 7
7.5 \div 22.4
that 's what I think
3 0
3 years ago
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