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timurjin [86]
1 year ago
9

A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

arandomly chosen student. Find the mean score and interpret the result. Round the answers to two decimal places as needed.X5678 910P(x) 0.06 0.16 0.34 0.23 0.15 0.06Send data to ExcelThe mean isIf we were to give this quiz to more and more students, the mean score for these studentswould approach.dDdedo13

Mathematics
1 answer:
mart [117]1 year ago
7 0

Solution

Question 1:

- The formula for finding the mean score is that of the expected value formula. That is,

\begin{gathered} E(x)=\sum_{i=1}p_i\times x_i \\ where, \\ p=\text{ The probability of getting a score of }x\text{ } \\ x=\text{ The actual score} \end{gathered}

- Thus, the mean can be gotten as follows:

\begin{gathered} \sum px=5\left(0.06\right)+6\left(0.16\right)+7\left(0.34\right)+8\left(0.23\right)+9\left(0.15\right)+10(0.06) \\ =7.43 \end{gathered}

The mean score is 7.43

Question 2:

- The more students write the exam, the more the mean score will approach the theoretical mean score.

- The theoretical mean score is calculated above to be 7.43

- Thus, as more students write the quiz, their scores approach 7.43

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Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph
Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

y=-\frac{7}{4}x+4

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

y_1=mx+b

And the second one, that is perpedicular to the one above:

y_2=nx+c

The slope of the second one is the negative inverse of the first one:

n=-\frac{1}{m}

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

y-y_1=m(x-x_1)

replace with the coordinates of the point and the slope and calculate:

\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}

Subtract 7 to both sides of the equation to write it in slope-intercept form:

\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}

Now you can graph both lines

8 0
1 year ago
Quick!! I need help with this question!
d1i1m1o1n [39]

1. 60 / 1/8 * 3/4

2. 3/4 * 15

3. 7/8 / 3/4

3 0
3 years ago
It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many
aksik [14]
<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

8 0
3 years ago
The expression 21 - (2x + 3)2 + 4 (1 - 1) + z3 can be simplified into the form
mr Goodwill [35]

Answer:

A=z

B=-2

C=0

D=30

Step-by-step explanation:

First lets simply the equation

21 - (2x +3)2 + 4(1-1) + z^3

21 - (2x^2 + 9) + 4(0) + z ^3

21 - 2x^2 + 9 + z^3

- 2x^2 + z ^3 + 30

This means that:

A=z

B=-2

C=0

D=30

5 0
3 years ago
How do I solve this? PLEASE HELP TIME LIMIT
katrin [286]

im not sure how to explain it, but i know its b

6 0
2 years ago
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