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timurjin [86]
1 year ago
9

A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

arandomly chosen student. Find the mean score and interpret the result. Round the answers to two decimal places as needed.X5678 910P(x) 0.06 0.16 0.34 0.23 0.15 0.06Send data to ExcelThe mean isIf we were to give this quiz to more and more students, the mean score for these studentswould approach.dDdedo13

Mathematics
1 answer:
mart [117]1 year ago
7 0

Solution

Question 1:

- The formula for finding the mean score is that of the expected value formula. That is,

\begin{gathered} E(x)=\sum_{i=1}p_i\times x_i \\ where, \\ p=\text{ The probability of getting a score of }x\text{ } \\ x=\text{ The actual score} \end{gathered}

- Thus, the mean can be gotten as follows:

\begin{gathered} \sum px=5\left(0.06\right)+6\left(0.16\right)+7\left(0.34\right)+8\left(0.23\right)+9\left(0.15\right)+10(0.06) \\ =7.43 \end{gathered}

The mean score is 7.43

Question 2:

- The more students write the exam, the more the mean score will approach the theoretical mean score.

- The theoretical mean score is calculated above to be 7.43

- Thus, as more students write the quiz, their scores approach 7.43

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Answer:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Let X the random variable that represent the average household spent of a population, and for this case we know the distribution for X is given by:

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We are interested on this probability

P(X>200)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>0.6)=1-P(z

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