A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the roc
ky Beach 2.10s later. Just before the clam lands, what is (a) its horizontal component of velocity and (b) its vertical component of velocity? (c) How would your answers to parts (a) and (b) change if the speed of the crow were increased? Explain.
1 answer:
Given:
Speed = 2.70 m
Time, t = 2.10 seconds
Let's solve for the following:
• (a) The horizontal component of the velocity.
To find the horizontal component, apply the formula:
Where:
Vo is the initial speed = 2.70 m
θ = 0 degrees
Hence, we have:
The horizontal component of the velocity just before it lands is 2.70 m/s.
• (b) The vertical component of the velocity.
To find the vertical component, apply the formula:
Where:
g is the acceleration due to gravity = 9.8 m/s²
t is the time = 2.10 s
Hence, we have:
The vertical component of the velocity just before it lands is -20.58 m/s.
(c) Here, the initial speed is equal to the constant horizontal speed.
Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.
The initial vertical velocity is 0 m/s in both cases.
Therefore, in part (b) the vertical component will remain constant.
ANSWER:
(a) 2.70 m/s
(b) -20.58
(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.
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Answer:
The number of electrons emitted from the metal per second increases.
Explanation:
The photoelectric effect can be explained by thinking the incident light as made of many photons, each carrying an energy of
where h is the Planck constant and f is the light frequency. A photoelectron is extracted from the metal if the energy of the incoming photon, which hits the electron and gives all its energy, is at least equal to the work function of the metal, . Moreover, each photon of the incident light hits only one electron in the metal.
Given these premises, we can analyze each statement:
The work function of the metal decreases. --> FALSE. The work function is just the energy needed to extract photoelectrons from the metal: so, it depends only on the properties of the metal, and not on the intensity of the incident light.
The number of electrons emitted from the metal per second increases. --> TRUE. The intensity of the incident light is proportional to the number of photons contained in the light: so, the higher the intensity, the larger the number of photons that hit the electrons in the metal, the larger the number of electrons emitted.
The maximum speed of the emitted electrons increases. --> FALSE. The energy of the electrons emitted depends ONLY on the energy of the incoming photon, so it depends only on the frequency of the photon, not on the number of photon (intensity). In fact, only 1 photon at time hits 1 electron, so the intensity of the light does not affect the energy of the electrons (and so, it does not affect their speed)
The stopping potential increases. --> FALSE. The stopping potential is the potential needed to stop the electrons in the metal preventing them to escape the metal: this depends only on the energy of the electron, which does not depend on the intensity of the light, but only on its frequency.