Answer: 0.516 ft/s
Explanation:
Given
Length of ladder L=20 ft
The speed at which the ladder moving away is v=2 ft/s
after 1 sec, the ladder is 5 ft away from the wall
So, the other end of the ladder is at

Also, at any instant t

differentiate w.r.t.

Answer:
5.71×10¹⁴ Hz
Explanation:
Applying,
v = λf................. Equation 1
Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency
make f the subject of the equation
f = v/λ............. Equation 2
From the question,
Given: λ = 525 nm = 5.25×10⁻⁷ m,
Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s
Substitute these values into equation 2
f = (3.0×10⁸)/(5.25×10⁻⁷)
f = 5.71×10¹⁴ Hz
Hence the frequency of light is 5.71×10¹⁴ Hz
The answer to the given statement above would be FALSE. It is not true that chemicals in clouds can cause rainstorms to occur. Rather, rainstorms happen when cumulonimbus clouds are formed. Rainstorms include <span>moisture, unstable air and lift. Hope this answers your question.</span>
Aha! This is a fun question, likely AP Physics 1 if I'm not mistaken. This is how you solve it, you need the following equation.

Now on this question you don't need to actually use the mass and diameter of the earth as we are only
looking at the
factor of how much your weight would change, so you can just plug in some random numbers for the mass and radius. In my case I will use the original radius as being
2 meters and the original mass of the earth as being
20kg. You can actually just omit the mass of your body and the gravitational constant isn't necessary to be multiplied by because they will remain the same in both scenarios.
Original weight:


So the original weight in this circumstance is 5N. Now then if we double the mass to
40kg and the radius to
4m you will have the following.


So the original weight was 5N and after doubling the mass and radius the weight reduced to 2.5N. This means the factor which your weight would change by is .5 or decrease by 1/2.
I hope this helps you :) You can ask me if you have any additional physics questions.