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photoshop1234 [79]
3 years ago
9

Kepler's third law is founded on a mathematical formula that is based on the inverse relationship between a planet's orbital vel

ocity and its distance from _____. the sun the earth the moon some other entity
Physics
2 answers:
zepelin [54]3 years ago
6 0

Answer:

Kepler's third law is founded on a mathematical formula that is based on the inverse relationship between a planet's orbital velocity and its distance from <u>the Sun</u>.        

Explanation:

According to Kepler's third law of planetary motion, the square of period of orbit of a planet (P) is directly proportional to the cube of distance from the Sun (a).

P^2=\frac{4\pi^2 a^3}{GM}

It was derived from equating gravitation force with centripetal force:

\frac{GMm}{a^2}=\frac{mv^2}{a}

There is inverse relation between orbital velocity (v) and its distance from the sun (r)

Cloud [144]3 years ago
4 0
Kepler's third law is founded on a mathematical formula that is based on
the inverse relationship between a planet's orbital velocity and its distance
from the sun.
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A 20 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at
stellarik [79]

Answer: 0.516 ft/s

Explanation:

Given

Length of ladder L=20 ft

The speed at which the ladder moving away is v=2 ft/s

after 1 sec, the ladder is 5 ft away from the wall

So, the other end of the ladder is at

\Rightarrow y=\sqrt{20^2-5^2}=19.36\ ft

Also, at any instant t

\Rightarrow l^2=x^2+y^2

differentiate w.r.t.

\Rightarrow 0=2xv+2yv_y\\\\\Rightarrow v_y=-\dfrac{x}{y}\times v\\\\\Rightarrow v_y=-\dfrac{5}{19.36}\times 2=0.516\ ft/s

5 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. Calculate the frequency of this l
12345 [234]

Answer:

5.71×10¹⁴ Hz

Explanation:

Applying,

v = λf................. Equation 1

Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency

make f the subject of the equation

f = v/λ............. Equation 2

From the question,

Given: λ = 525 nm = 5.25×10⁻⁷ m,

Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s

Substitute these values into equation 2

f = (3.0×10⁸)/(5.25×10⁻⁷)

f = 5.71×10¹⁴ Hz

Hence the frequency of light is 5.71×10¹⁴ Hz

5 0
3 years ago
Chemicals in clouds can cause rainstorms to occur
Brilliant_brown [7]
The answer to the given statement above would be FALSE. It is not true that chemicals in clouds can cause rainstorms to occur. Rather, rainstorms happen when cumulonimbus clouds are formed. Rainstorms include <span>moisture, unstable air and lift. Hope this answers your question.</span>
5 0
3 years ago
Use the drop-down menus to show the development of the atomic theory from the oldest theory (1) to the most recent theory (5).
lesya692 [45]

Answer:

4

1

3

5

2

Explanation:

Just took the test

6 0
3 years ago
Read 2 more answers
By what factor would your weight change if the earth's diameter were doubled and its mass were also doubled?
coldgirl [10]
Aha! This is a fun question, likely AP Physics 1 if I'm not mistaken. This is how you solve it, you need the following equation.

F=G\frac{m_{1} *m_{2}}{r^2}

Now on this question you don't need to actually use the mass and diameter of the earth as we are only looking at the factor of how much your weight would change, so you can just plug in some random numbers for the mass and radius. In my case I will use the original radius as being 2 meters and the original mass of the earth as being 20kg. You can actually just omit the mass of your body and the gravitational constant isn't necessary to be multiplied by because they will remain the same in both scenarios.

Original weight:

F= \frac{20kg}{2^2m}
F=5N

So the original weight in this circumstance is 5N. Now then if we double the mass to 40kg and the radius to 4m you will have the following.

F= \frac{40kg}{(4)^2m}
F=2.5N

So the original weight was 5N and after doubling the mass and radius the weight reduced to 2.5N. This means the factor which your weight would change by is .5 or decrease by 1/2.

I hope this helps you :) You can ask me if you have any additional physics questions.
7 0
3 years ago
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