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Minchanka [31]
3 years ago
10

In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met

al are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?
Check all that apply. The choices are:

The work function of the metal decreases.
The number of electrons emitted from the metal per second increases.
The maximum speed of the emitted electrons increases.
The stopping potential increases.
Physics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

The number of electrons emitted from the metal per second increases.

Explanation:

The photoelectric effect can be explained by thinking the incident light as made of many photons, each carrying an energy of

E=hf

where h is the Planck constant and f is the light frequency. A photoelectron is extracted from the metal if the energy of the incoming photon, which hits the electron and gives all its energy, is at least equal to the work function of the metal, \phi. Moreover, each photon of the incident light hits only one electron in the metal.

Given these premises, we can analyze each statement:

The work function of the metal decreases.   --> FALSE. The work function is just the energy needed to extract photoelectrons from the metal: so, it depends only on the properties of the metal, and not on the intensity of the incident light.

The number of electrons emitted from the metal per second increases.   --> TRUE. The intensity of the incident light is proportional to the number of photons contained in the light: so, the higher the intensity, the larger the number of photons that hit the electrons in the metal, the larger the number of electrons emitted.

The maximum speed of the emitted electrons increases.   --> FALSE. The energy of the electrons emitted depends ONLY on the energy of the incoming photon, so it depends only on the frequency of the photon, not on the number of photon (intensity). In fact, only 1 photon at time hits 1 electron, so the intensity of the light does not affect the energy of the electrons (and so, it does not affect their speed)

The stopping potential increases. --> FALSE. The stopping potential is the potential needed to stop the electrons in the metal preventing them to escape the metal: this depends only on the energy of the electron, which does not depend on the intensity of the light, but only on its frequency.

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a projectile is fired from the ground with an initial horizontal velocity of 8 meters per second. its initial vertical velocityis 6 meters per second. whats is the "total/resultant" velocity of the projectile at its peak?


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if the separation between two masses is doubled, does the gravitational force between them increase or decrease? By what factor?
docker41 [41]

Answer:

increase by a factor of 4.

Explanation:

If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

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A 60kg60 kg board that is 6 m6 m long is placed at the edge of a platform, with 4 m4 m of its length extending over the edge. Th
scoundrel [369]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The minimum mass of M_1 = 90\  kg correct option is  E

Explanation:

 Free body diagram of the set up  in the question is shown on the third uploaded image

  The mass of board is  M = 60kg

   The length of the board is L =  6 \ m

    The length extending over the edge is L_e = 4 \ m

    The second mass is  M_2 = 30kg

Now to obtain M_1 we take moment about the edge of the platform

               M_1 g L_1 = Mg \frac{L}{2}  + M_2 g L_2

              M_1  L_1 = M \frac{L}{2}  + M_2  L_2

  Substituting value  

               M_1 (2) = (60)(1) + (30)(4)

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4 years ago
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Answer:

2 is the anwser I think

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3 years ago
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A police car with its 300-Hz siren is moving toward a warehouse at 30 m/s, intending to crash through the door. The sound bounce
Lady bird [3.3K]

Answer: The frequency heard will be f = 275.675Hz

Explanation: When an object emitting sound is moving, it occurs a phenomenon called Doppler shift or Doppler effect. What happens is that the sound gets higher when the moving object comes closer the observer and becomes lower after it passes, This change is due to the quantity of waves that passes through an area in an unit of time.

The formula to calculate the Doppler effect is as follows

f = (\frac{c}{c+Vs}) · f₀

f is the observed frequency;

c is the speed of sound;

Vs is velocity of the source;

f₀ is the emitted frequency of source;

Substituting and calculating,

f = \frac{340}{340+30} · 300

f = 275.675 Hz

Thus, the frequency heard by the police officer is 275.675Hz.

8 0
4 years ago
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