assuming that voltage remains constant, what happpens to the current in a wire as its diameter decreases?

1 answer:

6 0

A larger diameter wire has lower resistance. A lower resistance wire produces less heat for a given current flowing through it.

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Slow moving vehicles must display ___________ emblem at the rear to warn of their low speed.

KIM [24]

<span>Slow moving vehicles must display reflective emblem at the rear to warn of their low speed.

The sign consists of a triangle and the primary purpose is to prevent any sad incident to happen, as slow moving vehicle (SMV) can cause serious accidents due to the less visibility at various times, therefore the sign must be visible enough. </span>

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4 years ago

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Which is an indication that a chemical change to a substance has occurred? A. It changes shape. B. New substances are formed. C.

Levart [38]

Answer:

The answer would be D.

Explanation:

Seven Things That Indicate a Chemical Change Is Occurring

Gas Bubbles Appear. Gas bubbles appear after a chemical reaction has occurred and the mixture becomes saturated with gas. ...

Formation of a Precipitate. ...

Color Change. ...

Temperature Change. ...

Production of Light. ...

Volume Change. ...

Change in Smell or Taste.

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3 years ago

Traumatic brain injury such as concussion results when the head undergoes a very large acceleration. Generally, an acceleration

miss Akunina [59]

Answer:

1728.42857143 m/s²

0.00155883061577 s

259.264285715 m/s²

0.0103922041051 s

The child will get injured if he/she falls on a hardwood floor

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2gs\\\Rightarrow v=\sqrt{2gs+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.37+0^2}\\\Rightarrow v=2.69432737432\ m/s$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-2.69432737432^2}{2\times 2.1\times 10^{-3}}\\\Rightarrow a=-1728.42857143\ m/s^2$

Magnitude of deceleration is 1728.42857143 m/s²

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-2.69432737432}{-1728.42857143}\\\Rightarrow t=0.00155883061577\ s$

Time taken is 0.00155883061577 s

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-2.69432737432^2}{2\times 1.4\times 10^{-2}}\\\Rightarrow a=-259.264285715\ m/s^2$