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Paladinen [302]

2 years ago

9

Hola necesito una ayudita soy un estudiante y estoy con el trabajo de fisica es:¿Cómo se representan las Fuerzas? Representa las

siguientes fuerzas graficamente

1 answer:

True [87]2 years ago

6 0

Answer:

Las fuerzas se representan dibujando flechas sobre el cuerpo en el que actúan, por ejemplo, la fuerza que se aplica al empujar un barril. ... Para obtener la fuerza resultante, puede aprovecharse la representación gráfica mediante flechas.

Explanation:

Gracias!!!

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The force of magnitude F acts along the edge of the triangular plate. Determine the moment of F about point O. Find the general

Sever21 [200]

Answer:

The moment is 81.102 k N-m in clockwise.

Explanation:

Given that,

Force = 260 N

Side = 580 mm

Distance h = 370 mm

According to figure,

Position of each point

$O=(0,0)$

$A=(0,-b)$

$B=(h,0)$

We need to calculate the position vector of AB

$\bar{AB}=(h-0)i+(0-(-b))j$

$\bar{AB}=hi+bj$

We need to calculate the unit vector along AB

$u_{AB}=\dfrac{\bar{AB}}{|\bar{AB}|}$

$u_{AB}=\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}}$

We need to calculate the force acting along the edge

$\hat{F}=F(u_{AB})$

$\hat{F}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})$

We need to calculate the net moment

$\hat{M}=\hat{F}\times OA$

Put the value into the formula

$\hat{M}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})\times(-b\hat{j})$

$\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}((h\hat{i}+b\hat{j})\times(-b\hat{j}))$

$\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}(-bh\hat{k})$

$\hat{M}=-\dfrac{bhF}{\sqrt{h^2+b^2}}$

Put the value into the formula

$\hat{M}=-\dfrac{580\times10^{-3}\times370\times10^{-3}\times260}{\sqrt{(370\times10^{-3})^2+(580\times10^{-3})^2}}$

$\hat{M}=-81.102\ \hat{k}\ N-m$

Negative sign shows the moment is in clockwise.

Hence, The moment is 81.102 k N-m in clockwise.

5 0

3 years ago

Audio frequency range of a human ear is 20Hz - 20000 Hz. Express the range in terms of time period ? Answer needed urgently. Pl.

Feliz [49]

Using the term c in this case is a little confusing. It is more generic to use a general velocity, v. That way, in this case, we know to use the speed of sound.

wavelength*frequency=v

wavelength_20Hz = (345 m/s)/(1/20s)

<span>wavelength_20kHz = (345 m/s)/(1/20000s)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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5 0

2 years ago

How much work is done by the gravitational force when a 265-kg pile driver falls 2.80m?

sp2606 [1]

Answer:

i dont know why are u asking me

Explanation:

6 0

2 years ago

A pendulum consists of a stone with mass m swinging on a string of length L and negligible mass. The stone has a speed of v0 whe

Dmitriy789 [7]

Answer:

(a) $v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) $\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

(c) $E_{total} = \frac{1}{2}mv_0^2$

Explanation:

(a) The total mechanical energy of the system is conserved.

$K_A + U_A = K_B + U_B\\\frac{1}{2}mv_0^2 + 0 = \frac{1}{2}mv^2 + mgh \\h = L - L\cos(\theta) = L(1 - \cos\theta)\\\frac{1}{2}mv^2 = \frac{1}{2}mv_0^2 - mgL(1-\cos(\theta))\\v^2 = mv_0^2 - 2gL(1-\cos(\theta))\\v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) The conservation of energy states

$K_A + U_A = K_M + U_M\\\frac{1}{2}mv_0^2 + 0 = 0 + mgL(1-\cos(\theta))\\1-\cos(\theta) = \frac{v_0^2}{2gL}\\\cos(\theta) = 1-\frac{v_0^2}{2gL} = \frac{2gL-v_0^2}{2gL}\\\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

(c) As explained in part (a) the total mechanical energy of the system is equal to the initial kinetic energy, since the potential energy of the system at that point is zero.

$E_{total}= K_A + U_A = K_A + 0\\E_{total} = \frac{1}{2}mv_0^2$

8 0

3 years ago

Type the correct answer in the box. Use numerals instead of words. Frank has a sample of steel that weighs 80 grams. If the dens

ad-work [718]

Answer:

10cm^3

Explanation:

Given data

Mass of steel = 80grams

density of steel= 8 g/cm^3

We know that the formula for density is given as

density= mass/volume

make volume subject of formula

volume= mass/density

volume=80/8

volume= 10cm^3

Hence, the volume 10cm^3

8 0

2 years ago