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balu736 [363]
3 years ago
6

given a 60uC point charge located at the origin, find the total electric flux passing through: a) that portion of the sphere r=2

6 cm bounded by 0
Physics
1 answer:
Ann [662]3 years ago
5 0
<span>my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get D= 7.06*10^-5 c/m2

</span><span>NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2 calculate required region area with formula =double integral(r^2sintheta dtheta dphi) we get =.106m^2 now multiply D*Required region we get 7.5uc</span>
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To solve the exercise it is necessary to take into account the concepts of wavelength as a function of speed.

From the definition we know that the wavelength is described under the equation,

\lambda = \frac{c}{f}

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f = 2Hz

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Replacing we have,

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3 years ago
A wedge with a mechanical advantage of 0.78 is used to raise a house corner from its foundation. If the output force is 7500 N,
Zigmanuir [339]

Answer:

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3 years ago
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8 0
3 years ago
Light is incident on an air-water interface at an angle of 30 degree to the normal. What angle does the refracted ray make with
Vikentia [17]

Answer:

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As the ray of light travels from rarer medium to denser medium, that mean air to water, the refraction takes place.

According to Snell's law,

Refractive index of water with respect to air = Sin i / Sin r

Where, r be the angle of refraction

4 / 3 = Sin 30 / Sin r

0.75 = 2 Sin r

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6 0
3 years ago
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Explanation:

8 0
3 years ago
Read 2 more answers
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