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balu736 [363]
3 years ago
6

given a 60uC point charge located at the origin, find the total electric flux passing through: a) that portion of the sphere r=2

6 cm bounded by 0
Physics
1 answer:
Ann [662]3 years ago
5 0
<span>my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get D= 7.06*10^-5 c/m2

</span><span>NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2 calculate required region area with formula =double integral(r^2sintheta dtheta dphi) we get =.106m^2 now multiply D*Required region we get 7.5uc</span>
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g The electric field in a sinusoidal wave changes as E =125 N&gt;C2cos 311.2 * 1011 rad&gt;s2t +14.2 * 102 rad&gt;m2x] (a) In wh
Elan Coil [88]

Answer:

a) the propagation direction is x, b)   E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d)  f = 4.95 10¹¹ Hz, e)  λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

      E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

      E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

          E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

          C = E / B

          B = E / c

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          B = 41.67 10⁻⁸ T

d) the angular velocity is

          w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

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           f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

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          k = 14.2 10² rad / m

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          λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

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Answer: Runofff

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Explanation :

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