Answer:
First, the image moves in and out of focus too quickly, so that it is difficult to precisely adjust the focus. Second, you run the risk of crashing the objective into the slide. Use the coarse focus only with the 4x low power objective. You can use the fine focus knob with all objectives.
Explanation:
Answer:
(a) The speed of the first particle is 1.75 m/s. The speed of the second particle is 6.9 m/s after the collision.
(b) The speed of the first particle is 3.45 m/s in the negative direction. The speed of the second particle is 1.73 m/s.
(c) The final kinetic energy of the incident particle in part (a) and part(b) is 0.0031 J and 0.011 J, respectively.
Explanation:
(a)
In an elastic collision, both momentum and energy is conserved.
Combining these equations will give the speed of the second particle.
We can use this to find the speed of the first particle.
(b)
If m_2 = 10g.
The minus sign indicates that the first particle turns back after the collision.
(c)
The final kinetic energy of the particle in part (a) and part (b) is
(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in
(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s
(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:
(2<em>π</em> (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s
(c) The plane accelerates toward the center of the path with magnitude
<em>a</em> = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²
(d) By Newton's second law, the tension in the line is
<em>F</em> = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N
Explanation:
If the intensity of the yellow light increased, meaning more photons will strike the Potassium metal per unit area. This will cause more ejection of electrons from the metal and hence, the strength of current will also increase as we know that
I = Q/t, as the charge increase , the current will also increase.
