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icang [17]
3 years ago
12

The wavelength of a wave is the horizontal distance from a ________ to an adjacent ________.

Physics
2 answers:
goldenfox [79]3 years ago
5 0
<span>A. crest, crest

hope im right!(: </span>
aleksandr82 [10.1K]3 years ago
5 0
D, It's both crest to crest and trough to trough.
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It does not affect. The closest nebula is the Orion Nebula at more than 1300 light years from Earth. It is so remote that nothing that happens there can influence the Earth. The only influence is to have beautiful colors and shapes and to let us dream one day to go there and explore them.

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2 years ago
Two samples of water can have different densities. Which of these statements would best explain this fact?
emmainna [20.7K]
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8 0
3 years ago
How can you analyze a compound formula
STALIN [3.7K]

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Chemical formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound. If a compound's chemical formula cannot be reduced any more, then the empirical formula is the same as the chemical formula. Combustion analysis can determine the empirical formula of a compound, but cannot determine the chemical formula (other techniques can though). Once known, the chemical formula can be calculated from the empirical formula.

Explanation:

4 0
3 years ago
Problem Page Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 28. g o
sergejj [24]

Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

Solution : Given,

Mass of C_2H_6 = 28 g

Mass of O_2 = 190 g

Molar mass of O_2 = 32 g/mole

Molar mass of C_2H_6 = 30 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of C_2H_6 and O_2.

\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{28g}{30g/mole}=0.933moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{190g}{32g/mole}=5.94moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

From the balanced reaction we conclude that

As, 2 mole of C_2H_6 react with 7 mole of O_2

So, 0.933 moles of C_2H_6 react with \frac{7}{2}\times 0.933=3.26 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and C_2H_6 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of C_2H_6 react to give 4 mole of CO_2

So, 0.933 moles of C_2H_6 react to give \frac{4}{2}\times 0.933=1.87 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(1.87moles)\times (44g/mole)=82.3g

Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

6 0
3 years ago
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