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umka21 [38]
3 years ago
11

Two identical gliders on an air track are held together by a piece of string, compressing a spring between the gliders. While th

ey are moving to the right at a common speed of 0.325 m/s, someone holds a match under the string and burns it, letting the spring force the gliders apart. One glider is then observed to be moving to the right at 1.33 m/s. What velocity does the other glider have
Physics
1 answer:
baherus [9]3 years ago
3 0

Answer:

Explanation:

Both the gliders have same mass and same speed of .325 m /s .

The detachment of spring will create equal and opposite force on both of them , one force adding momentum to one and the other force reducing the momentum of the other . Since mass of both the gliders are same , change in velocity too will be same . Let change in velocity be v .

for forward moving glider

.325 + v = 1.33

v = 1.005 m /s

The other glider will have final velocity

= .325 - 1.005

= - .68 m /s

So other glider will go in opposite direction with velocity of .68 m /s .

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viktelen [127]

Answer: D(t) = 8.e^{-0.4t}.cos(\frac{\pi }{6}.t )

Explanation: A harmonic motion of a spring can be modeled by a sinusoidal function, which, in general, is of the form:

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For a Damped Harmonic Motion, i.e., when the spring doesn't bounce up and down forever, equations for displacement is:

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The equation of displacement, D(t), of a spring with damping factor is D(t)=8.e^{-0.4t}.cos(\frac{\pi}{6} .t).

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