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ElenaW [278]
3 years ago
15

Which list of radioisotopes contains an alpha emitter, a beta emitter, and a positron emitter?

Chemistry
2 answers:
MArishka [77]3 years ago
6 0

Answer: The correct option is 3.

Explanation: Radioisotopes which emits alpha-particle are known as alpha-emitters. These radioisotopes undergo alpha-decay.

The radioisotopes which emits beta-particle (_{-1}^0\beta ) are known as beta-emitters. These radioisotopes undergo beta-minus decay. In this decay a neutron gets converted to a proton and an electron.

The radioisotopes which emits positron-particle (_{+1}^0\beta ) are known as positron-emitters. These radioisotopes undergo beta-plus decay. In this type of decay a proton gets converted to a neutron.

From the given options,

Option 1: All the three radioisotopes undergoes beta-minus decay.

Option 2: Cs-137 and Tc-99 radioisotopes undergo beta-minus decay.

Fr-220 is a radioisotope which undergoes alpha-decay.

Option 3: Radioisotope Kr-85 undergoes beta-minus decay.

_{36}^{85}\textrm{Kr}\rightarrow _{37}^{85}\textrm{Rb}+_{-1}^0\beta

Radioisotope Ne-19 undergoes positron decay.

_{10}^{19}\textrm{Ne}\rightarrow _{9}^{19}\textrm{F}+_{+1}^0\beta

Radioisotope Rn-222 undergoes alpha decay.

_{86}^{222}\textrm{Rn}\rightarrow _{84}^{218}\textrm{Po}+_{2}^4\alpha

Option 4: All the three radioisotopes undergoes beta-minus decay processes.

Hence, from the above information, the correct option is 3.

vodka [1.7K]3 years ago
4 0
The answer is (3), they are β-, β+ and α decay mode. For (1), they are β-, β- and β- decay mode. For (2), they are β-, α and β-. For (4), they are α, α and α decay mode.
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<h2>Answer - 0.73%</h2>

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(Above is proportions I used to get the answer)

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3 years ago
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Answer:

\boxed{yeah}

Explanation:

CO_2 \:  is \: reduced \: to→C \: by \:  2M_g \: (the \: reducing \: agent): while \\ 2M_g \: is \: oxydized \: to→2M_gO \: by \:  CO_2 \: (the \: oxydizing \: agent)

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2 years ago
What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?
Veronika [31]
 The number  of C2H5OH  in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg  of water

that is 3M = moles of solute/ 4 Kg
multiply  both side by  4

moles of the  solute  is therefore = 12  moles

by use of Avogadro law constant

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what  about 12 moles

=12 moles/1 moles  x 6.02 x10^23 = 7.224 x10^24 molecules
3 0
3 years ago
Describe how experimental evidence led each of the following scientists: Dalton, Rutherford, Thompson, Chadwick and Bohr, to dev
nasty-shy [4]
Dalton Found out there was a small, hard indestructible sphere that is the smalles part of an element.He created his own Atomic Theory:
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6 0
3 years ago
HELP FAST 100 PTSCalculate the amount of heat needed to convert 100.0 g of liquid water at 25 °C to water at 100 °C.
Alex Ar [27]

Answer:

31,380 Joules

Explanation:

Given Data:

Mass = m = 100 g

Temperature 1 = = 25 °C

Temperature 2 = = 100 °C

Specific Heat Constant = c = 4.184

Change in Temp. = ΔT = 100 - 25 = 75 °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (100)(4.184)(75)

Q = 31, 380 Joules

Hope this helped!

~AH1807

4 0
3 years ago
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