CxHy + O2 --> x CO2 + y/2 H2O
Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound
Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound
Find the mass of C and H in the compound:
.430mol x 12 = 5.16 g C
.166mol x 1g = .166g H
When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.
Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).
In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).
Atoms<span> are </span>arranged in molecular compounds in groups.
<span>
For </span>covalent compounds<span>: </span>
<span>consider drawing the lewis structure of the covalent compound in question, putting the atom which is least electronegative (save hydrogen) in the center.
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Answer:
5 moles
Explanation:
Given data:
Number of moles of HCl = 5 mol
Number of moles of H₂O produced = ?
Solution:
Chemical equation:
HCl + NaOH → NaCl + H₂O
Now we will compare the moles of HCl with H₂O.
HCl : H₂O
1 : 1
5 : 5
5 moles of water will be produced.
Answer:
The grams of sodium chloride that will be made is 292.5 g. calculation. 2Na + Cl₂ → 2NaCl. step 1: calculate the moles of Na. moles = mass/molar mass. From periodic table the molar mass of Na = 23 g/mol. moles = 115 g/23 g / mol = 5 moles. Step 2 : use the mole ratio to determine the moles of NaCl. Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also = 5 moles.
Explanation:
We know sodium is a very active metal and chlorine is also a very reactive non-metal. Usually, metals like to eliminate electrons and non-metals such as halogens like to accept electrons. Sodium readily eliminate its last shell electrons become Na+ cation and chlorine accepts that electron to form Cl-anion.
