Answer:
184.6 BTU
Explanation:
The thermal efficiency for a Carnot cycle follows this equation:
η = 1 - T2/T1
Where
η: thermal efficiency
T1: temperature of the heat source
T2: temperature of the heat sink
These temperatures must be in absolute scale:
1000 F = 1460 R
50 F = 510 R
Then
η = 1 - 510/1460 = 0.65
We also know that for any heat engine:
η = L / Q1
Where
L: useful work
Q1: heat taken from the source
Rearranging:
Q1 = L / η
Q1 = 120 / 0.65 = 184.6 BTU
Known :
Q = 300 L/s = 0.3 m³/s
D1 = 350 mm = 0.35 m
D2 = 700 mm = 0.7 m
g = 9.81 m/s²
Solution :
A1 = πD1² / 4 = π(0.35²) / 4 = 0.096 m²
A2 = πD2² / 4 = π(0.7²) / 4 = 0.385 m²
hL = (kL / 2g) • (U1² - U2²)
hL = (kL / 2g) • Q² (1/A1² - 1/A2²)
hL = (1 / 2(9.81)) • (0.3²) • (1/(0.096²) - 1/(0.385²))
hL = 0.467 m
Answer: since safeguarding isn't possible distance and location must be used instead
False, it depends on the situation. If the lift is tilting or anything like I would then get down. Certain training will say to get out and see if you can keep lowering,
Answer:
4mA
Explanation:
For this problem, we will simply apply Ohm's law:
V = IR
V/R = I
I = V / R
I = 12 volt / 3kΩ
I = 4mA
Hence, the current in the circuit is 4mA.
Cheers.
