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mars1129 [50]
3 years ago
8

A three-phase voltage source with a terminal voltage of 22kV is connected to a three-phase transformer rated 5MVA 22kV/220V. The

transformer has a per-phase series impedance of 0.05 pu and is connected to a distribution line with series impedance of 0.01+0.05Ω per phase. The line supplies a balanced three-phase load rated 1MVA, 220V with 0.8 lagging power factor.
a. Draw the one-line diagram of the system described.
b. Draw the equivalent per phase circuit of the system indicating all impedances in per unit. Use 1MVA, 220V as the base at the load.
c. Calculate the real losses in the transmission line in kW.

Engineering
1 answer:
amid [387]3 years ago
6 0

Answer:

A) See Attachment B) See Attachment C) 186.153

Explanation:

C) Per phase Voltage= 220/∛3

                                  = 6.037

S=V²/Z

  = (6.037)²/(0.01+i0.05)

  = 62051.282-i310256.41

Active power losses per phase= 62.051kW

total Active power losses= 62.051×3

                                         =186.153kW

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A centimeter is Viooth of a meter, while a kilo-
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b. False

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What steps would you take to design an improved toothpaste container?
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Then recognize the limitation of the current design, what needed change. This will help in determining what is needed to be included and what should be removed based on identified customers need.

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7 0
2 years ago
A carbon resistor has a resistance of 976 ohms at 0 degrees C. Determine its resistance at 89 degrees C​
nignag [31]

Answer:

1028.1184 Ohms

Explanation:

<u>Given the following data;</u>

  • Initial resistance, Ro = 976 Ohms
  • Initial temperature, T1 = 0°C
  • Final temperature, T2 = 89°C

Assuming the temperature coefficient of resistance for carbon at 0°C is equal to 0.0006 per degree Celsius.

To find determine its new resistance, we would use the mathematical expression for linear resistivity;

R_{89} = R_{0} + R_{0}(\alpha T)

Substituting into the equation, we have;

R_{89} = 976 + 976*(0.0006*89)

R_{89} = 976 + 976*(0.0534)

R_{89} = 976 + 52.1184

R_{89} = 1028.1184 \ Ohms

5 0
3 years ago
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