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Murljashka [212]
3 years ago
12

Thin film deposition is a process where: a)-elemental, alloy, or compound thin films are deposited onto a bulk substrate! b)-Pho

sphatization is also applied c)-Zinc plating is also applied d)-None of the above
Engineering
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

(A) elemental, alloy, or compound thin films are deposited on to a bulk substrate

Explanation:

In film deposition there is process of depositing of material in form of thin films whose size varies between the nano meters to micrometers onto a surface. The material can be a single element a alloy or a compound.

This technology is very useful in semiconductor industries, in solar panels in CD drives etc

so from above discussion it is clear that option (a) will be the correct answer

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Check them to see if the cylinder is running rich or lean. This can be determined by looking at the electrodes on the plugs
Hope this helps.
7 0
3 years ago
Air at 40°C flow steadily through the pipe shown in Fig. 1 below. If P1 = 40 kPa (gage), P2 = 10 kPa (gage), D = 3d, Patm ≅ 100
Dafna1 [17]

Based on the average velocity at section 2, and the absolute pressures at both sectors, the average speed at section 1 is 2.226 m/s.

<h3>What is the average speed at section 1?</h3>

Density at P₁:

= (40 + 100) / (0.287 x  (40 + 273))

= 1.5585 kg/m³

Density at P₂:
= (10 + 100) / (0.287 x  (40 + 273))

= 1.2245 kg/m³

The average speed at section 1 is:

= (Density at P₂ x d² x 25.5) / (Density at P₁ x 9d²)

= 2.226 m/s

Find out more on average velocity at brainly.com/question/17444459.

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8 0
3 years ago
. For each of the following situations, determine if the diode below is in foward or reversebias(a) (2 points) V1 = 0 V, V2= 2V(
Mazyrski [523]

Assuming V1 is the anode and v2 the cathode (Anode is P region and Cathode is N)

Answer:

a) Reverse bias

b) Forward bias

c) Forward bias

Explanation:

Forward bias: It happens whenever the N region of the diode is more positive than the P region. Hence, the depletion zone increase ceasing the current through the circuit -> V1 -V2 < 0  

Reverse bias: It happens whenever the P region of the diode is more positive than the N region. In this case, the depletion zone begins to shrink, if enough voltage is applied current could go through the circuit -> V1 - V2 > 0

a) V = V1 - V2 = 0 - 2 = -2 -> -2 is smaller than zero therefore, we have reverse bias

b) V = V1 - V2 = 4.5 - 2.8 = 1.7 -> 1.7 is greater than zero therefore, we have forward bias

c9 V = V1 - V2 = -1 - -1.3 = 0.3 -> 0.3 is greater than zero therefore, we have forward bias

6 0
3 years ago
Stainless steel ball bearings (rho = 8085 kg/m3 and cp = 0.480 kJ/kg·°C) having a diameter of 1.2 cm are to be quenched in water
sveticcg [70]

Answer:

\dot Q = -2.341\,kJ

Explanation:

The rate of heat transfer from the balls to the air is:

\dot Q = \left[(800\,\frac{1}{min} )\cdot (\frac{1\,min}{60\,s} )\cdot(8085\,\frac{kg}{m^{3}})\cdot (\frac{4}{3}\pi )\cdot (6\times 10^{-3}\,m)^{3}\right]\cdot (0.480\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (850\,^{\textdegree}C-900\,^{\textdegree}C)\dot Q = -2.341\,kJ

3 0
4 years ago
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