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Tanzania [10]
4 years ago
5

According to fire regulations in a town, the pressure drop in a commercial steel, horizontal pipe must not exceed 2.0 psi per 25

0 ft of pipe for flow rates up to 500 gal/min. If the water temperature is never below 50˚F, what diameter pipe is needed?
Engineering
1 answer:
bonufazy [111]4 years ago
7 0

Answer:

6.37 inch

Explanation:

Thinking process:

We need to know the flow rate of the fluid through the cross sectional pipe. Let this rate be denoted by Q.

To determine the pressure drop in the pipe:

Using the Bernoulli equation for mass conservation:

\frac{P1}{\rho } + \frac{v_{2} }{2g} +z_{1}  = \frac{P2}{\rho } + \frac{v2^{2} }{2g} + z_{2} + f\frac{l}{D} \frac{v^{2} }{2g}

thus

\frac{P1-P2}{\rho }  = f\frac{l}{D} \frac{v^{2} }{2g}

The largest pressure drop (P1-P2) will occur with the largest f, which occurs with the smallest Reynolds number, Re or the largest V.

Since the viscosity of the water increases with temperature decrease, we consider coldest case at T = 50⁰F

from the tables

Re= 2.01 × 10⁵

Hence, f = 0.018

Therefore, pressure drop, (P1-P2)/p = 2.70 ft

This occurs at ae presure change of 1.17 psi

Correlating with the chart, we find that the diameter will be D= 0.513

                                                                                                      = <u>6.37 in Ans</u>

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Answer:

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Explanation:

1) We can calculate the gas pressure difference from the U-tube manometer by using the following hydrostatic formula:

\Delta P = \frac{S\cdot \rho_{w}\cdot g \cdot \Delta h}{1000} (Eq. 1)

Where:

S - Relative density, dimensionless.

\rho_{w} - Density of water, measured in kilograms per cubic meter.

g - Gravitational acceleration, measured in meters per square second.

\Delta h - Height difference in the U-tube manometer, measured in meters.

\Delta P - Gas pressure difference, measured in kilopascals.

If we know that S = 1.5, \rho_{w} = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and \Delta h = 0.286\,m, then the pressure difference is:

\Delta P = \frac{1.5\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.286\,m)}{1000}

\Delta P = 4.207\,kPa

The pressure difference is 4.207 kilopascals.

2) From Physics we remember that a pound per square unit equals 2.036 inches of mercury and 2.307 feet of water and we must multiply the given pressure by corresponding conversion unit: (p = 2.5\,psi)

p = 2.5\,psi\times 2.037\,\frac{in\,Hg}{psi}

p = 5.093\,in\,Hg

p = 2.5\,psi\times 2.307\,\frac{ft\,H_{2}O}{psi}

p = 5.768\,ft\,H_{2}O

2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

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4 years ago
Singularity is an important property of a square matrix. This is also known as degenerate. What is the value of the determinant
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Answer:

For a Singular matrix, the determinant must be equivalent to 0.

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Answer:

The solution to this question is 5.153×10⁻⁴(kmol)/(m²·s)

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Explanation:

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Where

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Hence the rate of diffusion of ammonia through the layer is

5.153×10⁻⁴(kmol)/(m²·s)

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