Answer:
NaNO3
Explanation:
Hello,
In this case, the required reaction is an acid-base neutralization reaction which is said to be:
There, we see that the sodium displaced the hydrogen in the nitric acid to form sodium nitrate a very used salt in the industry, so, as a result of that displacement, water is formed as the secondary neutralization product. For the above mentioned, answer is NaNO3
.
Best regards.
When the mixture is homogeneous
The emperical formula for benzene (C6H6) is “CH”.
The counter-current is the process that occurs in the excretory system. The limbs become the multiplier because of the active transport of the electrolytes that move out.
<h3>What is the loop of Henle?</h3>
The loop of Henle is the part of the excretory system and part of the nephron. It functions in minimizing the water loss in the excretion of urine. There are descending and ascending loops present.
The ascending loop is impermeable to water but permeable to the electrolytes, and hence the concentration of the sodium, potassium, and chloride ions are actively pumped. This makes the solution more concentrated in the ascending loop.
Therefore, the electrolyte concentration results in active transport.
Learn more about the loop of Henle here:
brainly.com/question/13191804
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Answer:
33.8 m
Explanation:
(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).
Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.
Step 2: Convert the mass of HNO₃ to moles.
Step 3: Convert the mass of water to kilograms.
Step 4: Calculate the molality.
(b)
Step 1
In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.
Step 2
The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:
68.0 g × (1 mol/63.01 g) = 1.08 mol
Step 3
The mass of water is 32.0 g = 0.0320 kg
Step 4
The molality of HNO₃ is:
m = moles of solute / kilograms of solvent
m = 1.08 mol / 0.0320 kg
m = 33.8 m
