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2 years ago

12

Consider the following reaction where K. = 9.52 10 2 at 350 K.

1 answer:

Harman [31]2 years ago

3 0

Answer:

The correct answer is A :))

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When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the

Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

$\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}$

For 1000 C, W = x grams

$\tt x=\dfrac{1000.e}{96500}=0.0104e$

For 5x grams :

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