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lyudmila [28]
3 years ago
12

A strike slip fault is a result of

Chemistry
1 answer:
11111nata11111 [884]3 years ago
8 0
<span>I think its horizontal compression!

Plz give me Brainlyest if i got it right?

</span>
You might be interested in
If 100 yards = 1 football field, what is the length, in meters, of 4.9<br> football fields?
Veseljchak [2.6K]
* Answer: 448.056 meters *
——
1 yard = .9144 meters (according to Google)
100 yards= 91.44 meters
——
100*4.9= 490 yards
490 yards = 448.056 meters

* 4.9 Football fields= 448.056 meters *

I hope this helps! :)
4 0
3 years ago
Who is responsible for proposing an influential model of working memory featuring a three-part system that allows individuals to
olga55 [171]

Answer:

The person in charge is: "Alan Baddeley."

Explanation:

Hope this helps!!!

Please mark as brainliest:)

8 0
3 years ago
aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid wat
aleksandr82 [10.1K]

Answer:

Explanation:

HCl    + NaOH     =    NaCl    +     H₂O.

1 mole   1 mole           1 mole          1 mole

6.93  g of hydrochloric acid = 6.93 / 36.5 = .189 mole of HCl

2.4 g of NaOH = 2.4 / 40 =  .06 mole of NaOH

NaOH is in short supply so it is the limiting reagent .

1  mole of NaOH reacts with 1 mole of HCl to give 1 mole of Water

.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water

Water formed = .06 mole

= .06 x 18 = 1.08 g

= 1.1 g

4 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M Na_2CO_3

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol

6 0
3 years ago
50 POINTS! ANSWER FAST!
Korvikt [17]

<u>Given:</u>

The initial energy of the electron Einitial = 16.32 * 10⁻¹⁹ J

The energy released i.e the change in energy ΔE = 5.4 * 10⁻¹⁹ J

<u>To determine:</u>

The final energy state Efinal of the electron

<u>Explanation:</u>

Since energy is being released, this suggests that Efinal < Einitial

i.e. ΔE = Einitial - Efinal

Efinal = Einitial - ΔE = (16.32 - 5.4)*10⁻¹⁹ = 10.92 * 10⁻¹⁹ J

Ans: A)

The electron moved down to an energy level and has an energy of 10.92 * 10⁻¹⁹ J

6 0
3 years ago
Read 2 more answers
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