Train A is moving at 100 kmh–1 through a station. Train B is also travelling at 100 kmh–1 through the station but in the opposit
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Answer:
Explanation:
Given
See attachment for connection
Required
Determine the time constant in (b)
First, we calculate the total capacitance (C1) in (a):
The upper two connections are connected serially:
So, we have:
Take LCM
Cross Multiply
Make the subject
The bottom two are also connected serially.
In other words, the upper and the bottom have the same capacitance.
So, the total (C) is:
The total capacitance in (b) is calculated as:
First, we calculate the parallel capacitance (Cp) is:
So, the total capacitance (C2) is:
Take LCM
Inverse both sides
Both (a) and (b) have the same resistance.
So:
We have:
Time constant is directional proportional to capacitance:
So:
Convert to equation
Make k the subject
Make T2 the subject
Substitute values for T1, C1 and C2
Hence, the time constance of (b) is 0.592 s
